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3 years ago

10

What is "The Devil's Lettuce"?

1 answer:

Nady [450]3 years ago

3 0

Dont smoke it... This will happen.

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Why is hydrogen the most common element in the universe?

Scorpion4ik [409]

The universe<span> today is observed to contain one helium atom for every ten or eleven atoms of </span><span>hydrogen</span>

8 0

3 years ago

Read 2 more answers

What is the percentage of water in the hydrate CoCl2 • 6H2O? Can someone help me with this one?

valkas [14]

Okay, to do this you have to work with the relative molecular mass (RMM). You can get this from looking at the periodic table.

The RMM for the whole molecule is:
58.933 + (2 x 35.453) + (12 x 1.008) + (6 x 15.9994) = 237.96

Then you work out the RMM for water:
(2 x 1.008) + 15.9994 = 18.0154

As there are 6 moles of water in this molecule then multiply the RMM of H2O by 6 = 108.0924

Finally, divide the total H2O RMM by the total molecule RMM and multiply by 100 to get a percentage:
(108.0925 / 237.96) x 100 = 45.42%

7 0

3 years ago

What is the oxidation state of each individual carbon atom in c2o42−?

MA_775_DIABLO [31]

Answer:

+3

Explanation:

The oxygen all have a -2 oxidation state. (peroxides are exceptions)

The chemical structure is symmetrical. Both carbon are equivalent.

2 (oxidation state of carbon) + 4 (oxidation state of oxygen) = charge of ion.

2 (oxidation state of carbon) + 4 (-2) = -2

oxidation state of carbon = +3

7 0

3 years ago

Read 2 more answers

Question 4 of 10

fredd [130]

Answer:

c

Explanation:

because of the law of gravity

6 0

3 years ago

4.33 g of 3-hexanol were obtained from 5.84 g of hex-3-ene. Determine the percentage yield of 3-hexanol. a Determine the moles o

Vilka [71]

<u>Answer:</u> The amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of hex-3-ene = 5.84 g

Molar mass of hex-3-ene = 82.14 g/mol

Putting values in equation 1, we get:

$\text{Moles of hex-3-ene}=\frac{5.84g}{82.14/mol}=0.0711mol$

The chemical equation for the conversion of hex-3-ene to 3-hexanol follows:

$\text{hex-3-ene}+H_2O\xrightarrow []{10\% H_2SO_4} \text{3-hexanol}$

By Stoichiometry of the reaction:

1 mole of hex-3-ene produces 1 mole of 3-hexanol

So, 0.0711 moles of hex-3-ene will produce = $\frac{1}{1}\times 0.0711=0.0711mol$ of 3-hexanol

Now, calculating the mass of 3-hexanol from equation 1, we get:

Molar mass of 3-hexanol = 102.2 g/mol

Moles of 3-hexanol = 0.0711 moles

Putting values in equation 1, we get:

$0.0711mol=\frac{\text{Mass of 3-hexanol}}{102.2g/mol}\\\\\text{Mass of 3-hexanol}=(0.0711mol\times 102.2g/mol)=7.27g$

To calculate the percentage yield of 3-hexanol, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of 3-hexanol = 4.33 g

Theoretical yield of 3-hexanol = 7.27 g

Putting values in above equation, we get:

$\%\text{ yield of 3-hexanol}=\frac{4.33g}{7.27g}\times 100\\\\\% \text{yield of 3-hexanol}=59.56\%$

Hence, the amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %

4 0

3 years ago