Question

Is this function periodic or non-periodic?

Answer 1

we can conclude that yes, the function is periodic with period T =  π/2

Is this function periodic or non-periodic?

A function is periodic if for any input X, there exists a value T (where T is the period) such that:

f(x) = f(x + T).

In this particular case, we are told that the period should be π/2, so let's check that.

We can see that:

f(π/4) = 1.2

If we add the period to the argument, we get:

π/4 + π/2 = π/4 + 2π/4 = 3π/4

Now, on the table we can see that:

f(π/4 +π/2 ) = f(3π/4) = 1.2

So at the moment, it seems to be periodic.

Let's try another point.

f(3π/2) = 0.6

If we add the period:

3π/2 + π/2 = 2π

And in the table we can see that:

f( 2π) = 0.6

So we can conclude that yes, the function is periodic with period T =  π/2

If you want to learn more about periodic functions:

brainly.com/question/6561461

#SPJ1