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klasskru [66]
2 years ago
8

Timothy wants to know how far his math class is from the orange tree across the street from the school. His feet are ideal feet

(meaning they are 1 foot long. 1 foot is 12 inches). Timothy finds that the orange tree is 159 feet from the door of the math classroom. He wants to know that distance in kilometers (km)
Physics
1 answer:
VMariaS [17]2 years ago
3 0

The conversion factor can be used to change values from one unit to another.

<h3>What is conversion factor?</h3>

The conversion factor can be used to change values from one unit to another. We know that there are various units that could be used for the measurement of a quantity. The conversion factor would enable us to change the unit in which a value is given.

Without the conversion factor, a value in meters can not be expressed in inch or a values expressed in torr be given in bars or millimeter mercury for ease of computation.

This ability to change from one value to another has made the solution of mathematical problems much easier and  helps us to have a better grasp of the computational procedure that could be used in the calculation that we want to do for a particular of given problem.

Now the conversion factor is;

1 foot = 3281 kilometers

Hence;

159 feet = 159 * 3281

= 521679 kilometers

Learn more about conversion factor:brainly.com/question/23510660

#SPJ1

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8 0
4 years ago
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
spayn [35]

Answer:

v_0 = 3.53~{\rm m/s}

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}

For the y-direction gives

v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t

Combining both equation yields the y_component of the final velocity

v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}

6 0
3 years ago
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