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zhuklara [117]
3 years ago
9

A car going 22 m/s increases its speed to pass a truck. Five seconds later the car is going 35 m/s. Calculate the acceleration o

f the car.
Variable
Equation
Solve

Physics
2 answers:
wel3 years ago
6 0

Answer:

a = 2.6 m/s

Explanation:

a = v - u / t

a = 35 m/s - 22 m/s /  5 seconds

a = 2.6 m/s^2

jonny [76]3 years ago
4 0

Answer:

I don't know

Explanation:

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Which sequence shows the chain of energy transfers that create surface currents on the ocean?
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2 years ago
BRAINLIEST!
Vlada [557]

The two tests used for measuring each of the following fitness areas are as follows:

     a) Cardiorespiratory fitness → The 2.4 km run test; Astrand treadmill test

     b) Muscle strength → Muscle Testing Scale,  Bench/Leg press

     c) Body Composition → DEXA Scan, Bioelectrical Impedance Analysis

      Cardiorespiratory fitness is the ability of the circulatory as well as the respiratory systems to deliver oxygen to the mitochondria of skeletal muscle for energy generation during physical activity.

     

      Cardiorespiratory fitness is a vital indicator of both physical and mental wellbeing. It can lower the chance of developing heart disease and type 2 diabetes. Cardiorespiratory fitness improves lung and heart health while also increasing emotions of well-being.

  • The astrand treadmill test is used widely for testing the fitness of cardiorespiratory. The usefulness of this test is used to assess a client's aerobic fitness.
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      Muscle strength refers to the capacity to move and lift items.  It is determined by the amount of power you can exert and the amount of weight you can lift within a short amount of time.

   

      The test used to determine the muscle strength can be:

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8 0
3 years ago
During a hard stop, a car and its passengers slow down with an acceleration of 8,0m/s^2. What magnitude force does a 50-kg passe
arlik [135]

Answer:

F = 400 N

Explanation:

Given,

The acceleration of the car, a = 8 m/s²

The mass of the passenger, m = 50 Kg

The force acting on a body is equal to the product of the mass and its acceleration

                                    F = m x a   newtons

Substituting the given values in the above equation,

                                     F = 50 Kg x 8 m/s²

                                        = 400 N

Hence, the force exerted by the person on the seat belt is, F = 400 N

7 0
3 years ago
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