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zhuklara [117]
2 years ago
9

A car going 22 m/s increases its speed to pass a truck. Five seconds later the car is going 35 m/s. Calculate the acceleration o

f the car.
Variable
Equation
Solve

Physics
2 answers:
wel2 years ago
6 0

Answer:

a = 2.6 m/s

Explanation:

a = v - u / t

a = 35 m/s - 22 m/s /  5 seconds

a = 2.6 m/s^2

jonny [76]2 years ago
4 0

Answer:

I don't know

Explanation:

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In class I mentioned that we used to show an actual ballistic pendulum where a rifle is shot into a heavy block to see how the b
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3 0
3 years ago
Consider three force vectors F~ 1 with magnitude 43 N and direction 38◦ , F~ 2 with magnitude 26 N and direction −140◦ , and F~
Rama09 [41]

Answer:

34.70 N

Explanation:

Given :

F~ 1 = 43 N in direction 38◦

F~ 2 = 26 N in direction −140◦

F~ 3 = 27 N in direction 110◦

Therefore,

F~x = 43 cos (38) + 26 cos (-140) + 27 cos (110)

      = 43  (0.7) + 26  (-0.7) + 27  (-0.3)

      =  3.8

F~y = 43 sin (38) + 26 sin (-140) + 27 sin (110)

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so, F~ = $ \sqrt{3.8^2 + 34.5^2}$

          = 34.70 N

6 0
2 years ago
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