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2 years ago

9

A car going 22 m/s increases its speed to pass a truck. Five seconds later the car is going 35 m/s. Calculate the acceleration o

f the car.
Variable
Equation
Solve

2 answers:

wel2 years ago

6 0

Answer:

a = 2.6 m/s

Explanation:

a = v - u / t

a = 35 m/s - 22 m/s / 5 seconds

a = 2.6 m/s^2

jonny [76]2 years ago

4 0

Answer:

I don't know

Explanation:

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A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit

likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

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So mass density $\mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m$

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So angular frequency $\omega =2\pi f=2\times 3.14\times 120=753.6rad/sec$

And amplitude A = 1.6 mm = 0.0016 m

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Power is given by $P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt$

From the relation we can see that power $P\ \propto\ A^2$

So if amplitude is halved then power will be $\frac{1}{4}$ times

So power will be equal to $\frac{0.2023}{2}=0.0505watt$

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3 years ago

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Answer:

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