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2 years ago

Please helppp nowwwwww

Physics

1 answer:

kogti [31]2 years ago

5 0

Answer:

4.) the dependent variable is the french fry

5.) the independent variable is the jar; whether it has a lid on or not

6.) there are plenty of control variables in this example, the type of jar (size, material of the jar, etc.), the type of french fry, the room that the jars are in, the air pressure in the room, how long the experiment is, etc.

7.) My conclusion would be that the french fry that has the most exposure to the air.

The moisture in the french fry is leaving the jar because it is exposed to the open air. It becomes stale. But because the other french fry is in the closed jar, it is not exposed to the air or any new type of bacteria that could've entered the open jar. It'll stay fresher longer because it is not exposed the way the fry in the open jar is.

Explanation:

The dependent variable is the variable that is being tested. It is the one that changes due to whatever is being placed upon it.

i.e. the dependent variable in an experiment that tests the growth rate of lima bean plants in different colored lighting is the lima bean plant. <em>Depending</em> on the color of the lighting, the lima bean plant will grow at different rates.

The independent variable is the variable that is changed or controlled by an experimenter

i.e. the independent variable in an experiment that tests the growth rate of lima bean plants in different colored lighting is the different colored lighting. The color of the lighting helps prove the hypothesis that the growth rate of a lima bean plant is dependent on the lighting. In other words, the color of the light is not dependent on the growth of the plant.

A control variable is a variable that cannot be changed and is constant throughout the entire experiment

i.e. temperature, gravity, pollutants in the air, air pressure, humidity, etc.

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A 39-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Viefleur [7K]

Answer:

The rate of change of the area when the bottom of the ladder (denoted by $b$ ) is at 36 ft. from the wall is the following:

$\frac{dA}{dt}|_{b=36}=-571.2\, ft^2/s$

Explanation:

The Area of the triangle is given by $A=h\times b$ where $h=\sqrt{l^2-b^2}$ (by using the Pythagoras' Theorem) and $b$ is the length of the base of the triangle or the distance between the bottom of the ladder and the wall.

The area is then

$A=\sqrt{l^2-b^2}b$

The rate of change of the area is given by its time derivative

$\frac{dA}{dt}=\frac{d}{dt}\left(\sqrt{l^2-b^2}\cdot b\right)$

$\implies \frac{dA}{dt}=\frac{d}{dt}\left(\sqrt{l^2-b^2}\right)\cdot b+\frac{db}{dt}\cdot\sqrt{l^2-b^2}$

$\implies\frac{dA}{dt}=\frac{1}{2\sqrt{l^2-b^2}}\frac{d}{dt}(l^2-b^2)\cdot b+\sqrt{l^2-b^2}}\cdot \frac{db}{dt}$ Product rule

$\implies\frac{dA}{dt}=-\frac{1}{2\sqrt{l^2-b^2}}\cdot 2\cdot b^2\cdot \frac{db}{dt}+\sqrt{l^2-b^2}}\cdot \frac{db}{dt}$ Chain rule

$\implies\frac{dA}{dt}=-\frac{1}{\sqrt{l^2-b^2}}\cdot b^2\cdot \frac{db}{dt}+\sqrt{l^2-b^2}}\cdot \frac{db}{dt}$

$\implies\frac{dA}{dt}=\frac{db}{dt}\left(-\frac{1}{\sqrt{l^2-b^2}}\cdot b^2+\sqrt{l^2-b^2}}\right)$

In here we can identify $b=36\, ft$ , $l=39$ and $\frac{db}{dt}=8\,ft/s$ .

The result is then

$\frac{dA}{dt}=8\left(-\frac{1}{\sqrt{39^2-36^2}}\cdot 36^2+\sqrt{39^2-36^2}}\right)=-571.2\, ft^2/s$

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2 years ago

As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over th

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Answer:

$4.048\times 10^{-7}\ m$

Explanation:

h = Planck's constant = $6.626\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

E = Energy = $4.91\times 10^{-19}\ J$

Wavelength ejected is given by

$\lambda=\dfrac{hc}{E}\\\Rightarrow \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{4.91\times 10^{-19}}\\\Rightarrow \lambda=4.048\times 10^{-7}\ m$

The maximum wavelength in angstroms of the radiation that will eject electrons from the metal is $4.048\times 10^{-7}\ m$

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