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muminat
3 years ago
10

How is energy conserved in a process of a heart beat

Physics
1 answer:
Westkost [7]3 years ago
3 0

Explanation:

energy conservation and fatigue management -tiredness is a common symptom of a heart attack and although rest is important activity is also required to facilitate a return to health. an occupational therapist said energy conservation and fatigue management is techniques to be implemented throughout the day. to help clients achieve their goals

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Leading edge flaps can be used to decrease (or eliminate) the leading edge suction peak at a desired lift coefficient. When airf
Alik [6]

Answer:

An investigation is made to determine the performance of simple thin airfoils in the slightly supersonic flow region with the aid of the nonlinear transonic theory first developed by von Kármán[1]. Expressions for the pressure coefficient across an oblique shock and a Prandtl-Meyer expansion are developed in terms of a transonic similarity parameter. Aerodynamic coefficients are calculated in similarity form for the flat plate and asymmetric wedge airfoils, and curves are plotted. Sample curves for a flat plate and a specific asymmetric wedge are plotted on the usual coordinate grid of Cl, Cd,andCmc/4versus angle of attack and Cl versus Mach Number to illustrate the apparent features of nonlinear flow.

Explanation:

5 0
3 years ago
Atoms of the same element that have the same number of protons but different numbers of neutrons are called_____
saveliy_v [14]
The answer is:  "isotopes" .
_________________________________________________
7 0
3 years ago
True or false forces in a force pair never cancel each other out
pishuonlain [190]
The answer is false
3 0
3 years ago
Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid
Serhud [2]

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

8 0
3 years ago
Which of the following tools can be used to determine humidity? Select all that apply
Y_Kistochka [10]
Thermometer there's others you can use but i know that's one of them
7 0
3 years ago
Read 2 more answers
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