Force that is of equal magnitude
B, the light should be travelling out of the optically dense medium to the optically less dense medium.
were d to read "... is greater than the critical angle" I'd agree with it. But it doesn't read that way ...
Which leaves b as the only one which I think is true. Which I find a bit odd.
Out of interest, TIR is often used in piping light down optical fibres, among many other applications.
The momentum<span> of a particle is defined as the product of its mass times its velocity. It is a vector quantity. Therefore, the momentum of the baseball would be as follows:
Momentum = mass x velocity
Momentum = 0.45 kg (25 m/s)
Momentum = 11.25 kg m/s</span>
Answer:
The kinetic energy of the clam at a height of 5.0 m is 5.19 J and the speed of the clam at that height is 9.71 m/s.
<u>Explanation:
</u>
<em>Mechanical energy is constant throughout the travel</em>, we know that <em>mechanical energy is calculated by adding potential energy and kinetic energy</em>. Potential energy = ,
Kinetic energy = and Mechanical energy = Kinetic energy is zero at initial point. Now mechanical energy of clam with m=0.11kg,g=9.81,h=9.8 m is = 0.11×9.81×9.8 = 10.58 J.
Mechanical energy of clam at a height of 5.0 m = =. We know that mechanical energy is constant hence, <em>mechanical energy of clam at height 9.8 m is equal to mechanical energy at height 5.0 m</em>. This is represented as following
10.58 = 10.58 – 5.39 = 5.19 = kinetic energy of the clam is 5.19 J.
Now speed of the clam at height 5.0 m is 5.19 = 94.36 = = 9.71 m/s. The speed of the clam is 9.71 m/s.