The magnitude of <span>the acceleration of the apple just after it is released would be 9.8 m/sec^2. The reason being that gravity would be the only force acting on the apple and the acceleration of the balloon would be totally unimportant. I hope that this is the answer that has actually come to your help.</span>
Idk but it must be hard tho
DIVIDE 1 BY 86400 TO CONVERT 1 SECOND INTO SOLAR DAY.
Answer:
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Answer:
0.5 rad / s
Explanation:
Moment of inertia of the disk I₁ = 1/2 MR²
M is mass of the disc and R is radius
Putting the values in the formula
Moment of inertia of the disc I₁ = 1/2 x 100 x 2 x 2
= 200 kgm²
Moment of inertia of man about the axis of rotation of disc
mass x( distance from axis )²
I₂ = 40 x 1.25²
= 62.5 kgm²
Let ω₁ and ω₂ be the angular speed of disc and man about the axis
ω₂ = tangential speed / radius of circular path
= 2 /1.25 rad / s
= 1.6 rad /s
ω₁ = ?
Applying conservation of angular moment ( no external torque is acting on the disc )
I₁ω₁ = I₂ω₂
200 X ω₁ = 62.5 X 1.6
ω₁ = 0.5 rad / s