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meriva
2 years ago
15

Which expression is equivalent to

5} x^{0}" alt="-4x^{-5} x^{0}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Ber [7]2 years ago
7 0

The expression that is equivalent to the given expression is -4x^-5

<h3>How to determine which expression is equivalent to the given expression?</h3>

The expression is given as:

-4x^{-5} x^{0}

Rewrite properly as

-4x^-5x^0

Express as products

-4x^-5 * x^0

The value of x^0 is 1

So, we have:

-4x^-5 * 1

Evaluate the product

-4x^-5

Hence, the expression that is equivalent to the given expression is -4x^-5

Read more about equivalent expressions at:

brainly.com/question/2972832

#SPJ1

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At which root does the graph of f(x)=(x+4)^6(x+7)^5 cross the x axis​
jarptica [38.1K]

Answer:

-7.

Step-by-step explanation:

At the point -4 the graph just touches the x axis ( as its an even power) but at x = -7 it crosses the x axis ( because of the odd power 5).

The graph rises from the left and pass through the x axis at  (-7,0).

7 0
3 years ago
If the lines are parallel with angle a measuring 5x + 8 and angle b measuring 8x - 7, the measure of angle a would be ___ degree
Mandarinka [93]

The value of angle a will be 33°.

It should be noted that when we've parallel lines, then the angles will be equal. In this case, the value of angle a will be equal to that of angle b and this will be:

5x + 8 = 8x - 7.

Collect like terms .

8x - 5x = 8 + 7

3x = 15

Divide both side by 3

3x/3 = 15/3

x = 5

Therefore, the value of angle a will be:

= 5x + 8

= 5(5) + 8

= 25° + 8°

= 33°

The measure of angle a is 33°.

Read related link on:

brainly.com/question/24576134

7 0
3 years ago
Problem 5
ddd [48]

Answer:

100000000.09068588606047357608487007037864776060797704ww

Step-by-step explanation:

it is on gole

3 0
3 years ago
Simplify (3x2y)(5x3y−1)
ludmilkaskok [199]

Answer:

6xy(15xy−1)

Step-by-step explanation:

3 0
3 years ago
How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?
elena-s [515]

Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have

\dfrac{2.5}{x+10}=0.1\implies25=x+10\implies x=15

and so you would need to add 15 L of pure water to get the desired concentration of acid.

8 0
4 years ago
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