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bogdanovich [222]
2 years ago
8

A neutron star is:__-.

Physics
1 answer:
r-ruslan [8.4K]2 years ago
3 0

Left over from the death of a massive star.

<h3>What are neutron stars?</h3>

A neutron famous person is the collapsed middle of a big supergiant celebrity, which had a complete mass of among 10 and 25 sun hundreds, possibly more if the megastar was specially metallic wealthy.

Except for black holes and some hypothetical objects (e.g., white holes, quark stars, and peculiar stars), neutron stars are the smallest and densest presently regarded class of stellar items.

Neutron stars have a radius at the order of 10 kilometers and a mass of approximately Four sun masses.

They end result from the supernova explosion of a large superstar, blended with gravitational collapse, that compresses the center beyond white dwarf famous person density to that of atomic nuclei.

To know more about this, follow the link below:

brainly.com/question/14604351

#SPJ4

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Identical objects, Object X and Object Y, are tied together by a string and placed at rest on an incline, as shown in the figure
goblinko [34]

The slope of the velocity time graph of an object moving with constant acceleration is constant

It will take approximately <u>3 seconds</u> for the center of mass of Object X to reach point J near the bottom of the incline

The reason why the above time value is correct is given as follows:

Known parameters:

Initial velocity of the objects, u = 0

The graph  in the question is a straight line graph with data points

(0, 0), (0.5, 1.0), (1.0, 2), (3.0, 6), and (3.5, 7)

Given that the slope of the velocity-time graph is constant, we have that the acceleration is constant and is given as follows;

a = \dfrac{\Delta v}{\Delta t } = \dfrac{v_2 - v_1}{t_2 - t_1}

Therefore;

a =  \dfrac{6 - 2}{3.0 - 1.0} = 2

The acceleration, a ≈ 2 m/s²

The distance from the center of mass of the Object X to the point J near the bottom = 9 m

The equation for distance travelled is given as follows;

s = u\cdot t + \dfrac{1}{2} \cdot a \cdot t^2

Which gives;

9 =  0\times t + \dfrac{1}{2} \times 2 \times t^2 = t^2

t = √9 = 3

The time it will take the center of mass of Object X to reach point J near the bottom of the incline is t = <u>3 seconds</u>

Learn more about motion under constant acceleration here:

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What is the correct term for the flow of charged particles?
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If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If i
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