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Crank
3 years ago
12

A boxcar at a rail yard is set into motion at the top of a hump. The car rolls down quietly and without friction onto a straight

, level track where it couples with a flatcar of smaller mass, originally at rest, so that the two cars then roll together without friction. Consider the two cars as a system from the moment of release of the boxcar until both are rolling together. (a) is the mechanical energy of the system conserved? (b) is the momentum of this system conserved? Next, consider only the process of the boxcar gaining speed as it rolls down the hump. Consider the boxcar and the Earth as a system. (a) is the mechanical energy of the system conserved? (b) is the momentum of this system conserved? Finally, consider the two cars as a system as the boxcar is slowing down in the coupling process. (a) is the mechanical energy of the system conserved? (b) is the momentum of this system conserved?

Physics
1 answer:
enyata [817]3 years ago
3 0

Answer:

I have answer with explanations in each of the six (6) special cases.

Explanation:

Please find attached the detailed solution to all your questions.

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Car A, moving in a straight line at a constant speed of 20. meters per second, is initially 200 meters behind car B, moving in t
MA_775_DIABLO [31]
First, let's express the movement of Car A and B in terms of their position over time (relative to car B)
For car A: y=20x-200   Car A moves 20 meters every second x, and starts 200 meters behind car B
For Car B: y= 15x      Car B moves 15 meters every second and starts at our basis point

Set the two equations equal to one another to find the time x at which they meet:
20x - 200 = 15x
200 = 5x 
x= 40
At time x=40 seconds, the cars meet. How far will Car A have traveled at this time? 
Car A moves 20 meters every second:
20 x 40 = 800 meters
8 0
3 years ago
Describe liquids and GASSES IN TERMS OF THERE VOLUME AND SHAPES
antiseptic1488 [7]

Answer:

Explanation:

liquids have definite volume

liquids do not have definite shape. The take the shape of the container in which they are kept.

gases do not have definite volume.

gases do not have definite shape. They take the shape of the container in which they are kept.

Hope this helps

plz mark as barinliest!!!!!!

Stay safe!

3 0
3 years ago
Read 2 more answers
An alien from the newly discovers planet nine weighs himself on his planet and finds his weight to be 3200 N. When he stoves on
White raven [17]

Answer:

2.45 m/s²

Explanation:

From the question,

On the Earth

W = mg.................. Equation 1

Where W = weight of the alien on the earth, m = mass of the alien on the earth, g = acceleration due to gravity of the earth.

Make m the subject of equation 1

m = W/g................... Equation 2

Given: W = 3200 N

Constant: 9.8 m/s²

Substitute these value into equation 2

m = 3200/9.8

m = 326.5 kg.

Similarly,

On planet 9,

W' = mg'............... Equation 3

Where W' = weight of the alien on planet 9, g' = acceleration due to gravity on planet 9.

make g' the subject of the equation

g' = W'/m............ Equation 4

Given: W' = 800 N

Substitute into equation 4

g' = 800/326.5

g' = 2.45 m/s²

5 0
3 years ago
beautiful patterns are formed in a kaleidoscope because of multiple reflection . explain and specify how it is different from a
Ivahew [28]

Periscope is a tube containing mirrors or prisms for seeing things which are otherwise not possible to see due to some obstacle. Two mirrors are aligned at 45 degrees through which light bounces off and enables the observer to see beyond the obstacle. This is specially used in submarines.

A kaleidoscope is an optical device which contains mirrors and colored glass pieces in a tube. When the tube is rotated, beautiful patterns are formed due to multiple reflections.  

8 0
3 years ago
A piano tuner stretches a steel piano wire with a tension of 800 N. The steel wire is 0.400 m long and has a mass of 3.00 g. Wha
stepan [7]

Answer:

408.25 Hz.

Explanation:

The fundamental frequency of a stretched string is given as

f' = 1/2L√(T/m') .................... Equation 1

Note: The a steel piano wire is a string

Where f' = fundamental frequency of the wire, L = length of the wire, T = tension on the wire, m' = mass per unit length of the wire.

Given: L = 0.4 m, T = 800 N,

Also,

m' = m/L where m = mass of the steel wire = 3.00 g = 3/1000 = 0.003 kg.

L = 0.4 m

m' = 0.003/0.4 = 0.0075 kg/m.

Substituting into equation 1

f' = 1/(2×0.4)[√(800/0.0075)]

f' = 1/0.8[√(106666.67)]

f' = 326.599/0.8

f' = 408.25 Hz.

Hence the frequency of the fundamental mode of vibration = 408.25 Hz.

8 0
3 years ago
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