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grigory [225]
4 years ago
15

The maximum strength of the earth's magnetic field is about 6.9 10-5 T near the south magnetic pole. In principle, this field co

uld be used with a rotating coil to generate 60.0-Hz ac electricity. What is the minimum number of turns (area per turn
Physics
1 answer:
Ganezh [65]4 years ago
7 0

Answer:

Number of turns, N=5\times 10^5

Explanation:

Given that,

The maximum strength of the Earth's magnetic field, B=6.9\times 10^{-5}\ T

This field could be used with a rotating coil to generate 60.0-Hz ac electricity.

Let us assume that the coil must have to produce an rms voltage of 120 V and area per turn is 0.022 meter square.

\epsilon=\sqrt{2} V_{rms}\\\\\epsilon=\sqrt 2\times 120\\\\\epsilon=169.7\ V

The emf induced in the coil is given by :

\epsilon=NAB\omega\\\\\epsilon=2\pi NABf

N is the number of turns

f is the frequency

N=\dfrac{\epsilon}{2\pi ABf}\\\\N=\dfrac{169.7}{2\pi 0.022\times 6.9\times 10^{-5}\times 60}\\\\N=2.96\times 10^5

or

N=5\times 10^5

So, there are 5\times 10^5 turns in the coil.

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3 years ago
A watering can is most likely measured in which metric unit
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3 years ago
A lightning rod effectively protects a building by transferring the electrical current to the ____________.
maria [59]
It transfers the electrical current from the point of contact on the lightning rod into the ground.
6 0
3 years ago
A roadway for stunt drivers is designed for racecars moving at a speed of 40 m/s. A curved section of the roadway is a circular
Fynjy0 [20]

Answer:

Bank angle = 35.34o

Explanation:

Since the road is frictionless,

Tan (bank angle) = V^2/r*g

Where V = speed of the racing car in m/s, r = radius of the arc in metres and g = acceleration due to gravity in m/s^2

Tan ( bank angle) = 40^2/(230*9.81)

Tan (bank angle) = 0.7091

Bank angle = tan inverse (0.7091)

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3 0
3 years ago
A boat has a mass of 4040 kg. Its engines generate a drive force of 4660 N due west, while the wind exerts a force of 880 N due
maxonik [38]

Answer:

Explanation:

Given:

Mass of the boat, m = 4040 kg

The driving force of engine, FB = 4660 N in west = + 4660 N

The force of wind, Fwi = 880 N in east = -880 N

The force of water, Fwa = 1400 N in east = -1400N

Total three forces are acting on the boat

Fnet= Fb+fwi+Fwa

Fnet= 4660 - 880 - 1400

Fnet= +2380N

Acceleration (a) = Force/mass

= 2380/4040

= 0.59m/s2

6 0
3 years ago
Read 2 more answers
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