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2 years ago

Draw structures from the following names, and determine which compounds are optically active:(b) 3-chloro-2,2,5-trimethylhexane

Chemistry

1 answer:

inn [45]2 years ago

7 0

The given compound 3-chloro-2,2,5-trimethylhexane is an optically active compound .

Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .

It has chiral center.

Here the chiral carbon has 4 distinct groups such as : chlorine , hydrogen , 2-methylpropyl , tertbutyl .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

Learn more about chiral center here:

brainly.com/question/9522537

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An exothermic reaction __________ energy.

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It releases energy (what I am saying in other words that "D. Releases" would be your answer)

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under certain water conditions, the free chlorine (hypochlorous acid, hocl) in a swimming pool decomposes according to the la

ivolga24 [154]

Answer:

1.7 ppm

Explanation:

Original amount N' = 2.6 ppm

time to testing t = 24 hr

final amount N = 2.1 ppm

Using exponential inhibited decay, we have

N = N'e^(-kt)

Where

N is the new reading

N' is the original reading

t is the decay time

k is the decay constant

Substituting, we have

2.1 = 2.6 x e^(-k x 24)

2.1 = 2.6 x e^(-24k)

0.808 = e^(-24k)

We take the natural log of both sides of the equation

Ln 0.808 = Ln (e^(-24k))

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K = 0.213/24 = 0.00886

After 48 hrs, the reading of free chlorine will be

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5 0

3 years ago

50 points I need help on this whole work sheet about converting moles

kozerog [31]

Answer:

Explanation:

11)

Answer:

9.08 mol

Given data:

Number of moles of P₂O₅ = ?

Number of moles of O₂ = 22.7 mol

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

O₂ : P₂O₅

5 : 2

22.7 : 2/5×22.7 = 9.08

12)

Answer:

7 mol

Given data:

Number of moles of P₂O₅ = ?

Number of moles of P = 14 mol

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P₂O₅ with P.

P : P₂O₅

4 : 2

14 : 2/4×14 = 7

13)

Answer:

76.25 mol

Given data:

Number of moles of P = 61 mol

Number of moles of O₂ react = ?

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P with O₂.

P : O₂

4 : 5

61 : 5/4×61 = 76.25

14)

Answer:

1.25 mol

Given data:

Number of moles of P₂O₅ = 0.5 mol

Number of moles of O₂ needed = ?

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

P₂O₅ : O₂

2 : 5

0.5 : 5/2×0.5 = 1.25

15)

Answer:

20 mol

Given data:

Number of moles of P₂O₅ = 8 mol

Number of moles of O₂ needed = ?

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

P₂O₅ : O₂

2 : 5

8 : 5/2×8 = 20

16)

Answer:

12 mol

Given data:

Number of moles of silver made = ?

Number of moles of Ag₂O = 6 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles of Ag with Ag₂O .

Ag₂O : Ag

2 : 4

6 : 4/2×6 = 12

17)

Answer:

25 mol

Given data:

Number of moles of silver made = ?

Number of moles of O₂ produced = 6.25 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles of Ag with O₂ .

O₂ : Ag

1 : 4

6.25 : 4×6.25 = 25

18)

Answer:

9.8 mol

Given data:

Number of moles of silver made = ?

Number of moles of O₂ produced = 2.45 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles of Ag with O₂ .

O₂ : Ag

1 : 4

2.45 : 4×2.45 = 9.8

19)

Answer:

4.4 mol

Given data:

Number of moles of silver oxide required = ?

Number of moles of O₂ produced = 2.2 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles Ag₂O of with O₂ .

O₂ : Ag₂O

1 : 2

2.2 : 2×2.2 = 4.4

20)

Answer:

1.5 mol

Given data:

Number of moles of silver oxide required = ?

Number of moles of O₂ produced = 0.75 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles Ag₂O of with O₂ .

O₂ : Ag₂O

1 : 2

0.75 : 2×0.75 = 1.5

8 0

4 years ago

WILL MARK BRAINLIEST IF YOU ANSWER WITHIN 5 MINUTES

tensa zangetsu [6.8K]

Answer:

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Explanation:

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6 0

3 years ago

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