-130KJ is the standard heat of formation of CuO.
Explanation:
The standard heat of formation or enthalpy change can be calculated by using the formula:
standard heat of formation of reaction = standard enthalpy of formation of product - sum of enthalpy of product formation
Data given:
Cu2O(s) ---> CuO(s) + Cu(s) ∆H° = 11.3 kJ
2 Cu2O(s) + O2(g) ---> 4 CuO(s) ∆H° = -287.9 kJ
CuO + Cu ⇒ Cu2O (-11.3 KJ) ( Formation of Cu2O)
When 1 mole Cu20 undergoes combustion 1/2 moles of oxygen is consumed.
Cu20 + 1/2 02 ⇒ 2CuO (I/2 of 238.7 KJ) or 119.35 KJ
So standard heat of formation of formation of Cu0 as:
Cu + 1/2 02 ⇒ CuO
putting the values in the equation
ΔHf = ΔH1 + ΔH2 (ΔH1 + ΔH2 enthalapy of reactants)
heat of formation = -11.3 + (-119.35)
= - 130.65kJ
-130.65 KJ is the heat of formation of CuO in the given reaction.
A unit of ppm has an acronym of parts per million. The
equivalent units of ppm is therefore mg/L and mg/kg. So the ppm is:
mass Ca+ = 1.3 g = 1300 mg
ppm = 1300 mg / 3100 kg
<span>ppm = 0.42 ppm</span>
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Phosphorus is the correct answer.
Answer:
Oxygen, and from solid to liquid. This is because oxygen's melting point is at -218°C. Melting point refers to the temperature where heat causes particles to vibrate with sufficient energy to break the solid structure, so for oxygen this means it's being turned into a liquid.
