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Vilka [71]
3 years ago
5

4 AlF3 + 3 O2 ----------> 2Al2O3 + 6 F2

Chemistry
1 answer:
anyanavicka [17]3 years ago
8 0

Explanation:

6 F2------->4 AlF3

F2-----------> 4/6 AlF3

8.25 F2 ---------> 4×8.25/6 AlF3

so 5.5 moles

You might be interested in
Na2CO3(aq) + CaCl2(aq) — 2 NaCl(aq) + CaCO3(s)
attashe74 [19]

Answer:

100 mL

Explanation:

Given data:

Mass of CaCO₃ produced = 2.00 g

Molarity of CaCl₂ = 0.200 M

Volume of CaCl₂ needed = ?

Solution:

Chemical equation:

Na₂CO₃  + CaCl₂    →      2NaCl + CaCO₃

First of all we will calculate the number of moles of CaCO₃.

Number of moles = mass/molar mass

Number of moles = 2.00 g / 100.09 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of CaCO₃ and CaCl₂.

              CaCO₃          :            CaCl₂

                   1                :               1

                 0.02           :              0.02

Thus, 0.02 moles of CaCl₂ react,

Volume of CaCl₂ reacted:

Molarity = number of moles / volume in L

0.200 M = 0.02 mol / volume in L

Volume in L = 0.02 mol / 0.200 M

Volume in L = 0.1 L

Volume in mL:

0.1 L × 1000 mL/1L

100 mL

5 0
3 years ago
Light ray 1 strikes the smooth surface, separating air and water as shown below. A horizontal line is drawn and the part above t
FinnZ [79.3K]

I think the correct answer is ray 2.

8 0
3 years ago
Read 2 more answers
11.
Lostsunrise [7]

Answer:

(1) -12 Kcal/mol

Explanation:

Our answer options for this question are:

(1) -12 Kcal/mol

(2) -13 Kcal/mol

(3) -15 Kcal/mol

(4) -16 Kcal/mol

With this in mind, we can start with the chemical reaction (Figure 1). In this reaction, <u>two bonds are broken</u>, a C-H and a Br-Br. Additionally, a C-Br and a H-Br are <u>formed</u>.

If we want to calculate the enthalpy value, we can use the equation:

<u>ΔH=ΔHbonds broken-ΔHbonds formed</u>

If we use the energy values reported, its possible to calculate the energy for each set of bonds:

<u>ΔHbonds broken</u>

<u />

C-H = 94.5 Kcal/mol

Br-Br = 51.5 Kcal/mol

Therefore:

105 Kcal/mol + 53.5 Kcal/mol = 146 Kcal/mol

<u>ΔHbonds formed</u>

C-Br = 70.5 Kcal/mol

H-Br = 87.5 Kcal/mol

Therefore:

70.5 Kcal/mol + 87.5 Kcal/mol = 158 Kcal/mol

<u>ΔH of reaction</u>

<u />

ΔH=ΔHbonds broken-ΔHbonds formed=(146-158) Kcal/mol = -12 Kcal/mol

I hope it helps!

<u />

6 0
3 years ago
1. As the temperature of the gas in a balloon decreases, which of the following occurs? The volume of the balloon increases. ***
timama [110]
Answer 1:
Correct Answer: T<span>he average kinetic energy of the gas decreases.
</span>Reason: 
From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume, n = number of moles of gas, R = gas constant and T = temperature.

From above equation, it can be seen that, Temp. as a direct relation with Pressure and Volume. Hence, as temperature of the gas in a balloon decreases, pressure and volume also decreases. 

Also, from kinetic theory of gases, we know that, kinetic energy of gas increases with increasing temp. Hence,  average kinetic energy of the gas decreases with decreasing temp.  

Answer 2: 
Correct answer: Out
Reason: 
From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume, n = number of moles of gas, R = gas constant and T = temperature.

Therefore, when a sealed syringe is heated, it's temp. will increase. This, will result in expansion of gas i.e volume will increase. Hence, <span>syringe plunger move in outwards direction.

Answer 3: Volume = 6046 L
Reason: 
</span>From the ideal gas equation, we know that PV = RT
where, P = pressure, V = volume, R = gas constant and T = temperature.<span>
Given: P1 = 99 kPa, V1 = 3000 L, T1 = 312 K, P2 = 45.5 KPa and  T2 = 289 K.

Therefore, we have: </span>\frac{\text{P1 V1}}{\text{P2 V2}} =  \frac{\text{R T1}}{\text{R T2}}
Thus, \frac{\text{99 3000}}{\text{45.5 V2}} = \frac{\text{R 312}}{\text{R 289}}

Hence, V2 = 6046 L

Answer 4: 
Correct Answer: It increases
Reason: 
We know that, pressure of gas, it directly proportional to temp. Hence, when the temp. of as is increases. Total pressure of gas mixture increases. This is because, partial pressure of individual component (in present case oxygen) increases.

Answer 5: 
Correct answer: 18.5 kPa
Reason:
We know that, total pressure is the sum of the partial pressures of the gases present in it. Mathematically, it can be expressed as:

                           Ptot = PO2 + PHe + PCO2

Therefore,  partial pressure of oxygen, <span>PO2:</span>

                         PO2 = Ptot − PHe − PCO2

                                = 101.4 − 82.5 − 0.4

                                =18.5 kPa.


Answer 6: 

Correct Answer: Argon

Reason: 

<span>Inert gases are the best choice for inflating a balloon that must remain inflated for a long period of time. Among given options, both neon and argon are inert gas, But, atomic weight of Ar is 40g/mol, while is more than that of neon (20 g/mol). Hence,. Argon gas is preferred over neon gas. </span>
4 0
3 years ago
Read 2 more answers
How many grams of H2SO4 are needed to prepare 500. mL of a .250M solution?
zavuch27 [327]

Answer:

We need 12.26 grams H2SO4

Explanation:

Step 1: Data given

Volume of a H2SO4 solution = 500 mL = 0.500 L

Concentration of the H2SO4 solution = 0.250 M

Molar mass of H2SO4 = 98.08 g/mol

Step 2: Calculate moles H2SO4

Moles H2SO4 = concentration * volume

Moles H2SO4 = 0.250 M * 0.500 L

Moles H2SO4 = 0.125 moles

Step 3: Calculate mass of H2SO4

Mass of H2SO4 = moles * molar mass

Mass of H2SO4 = 0.125 moles * 98.08 g/mol

Mass of H2SO4 = 12.26 grams

We need 12.26 grams H2SO4

7 0
3 years ago
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