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djverab [1.8K]
3 years ago
14

How many calories are there in 32 Calories? a.64,000 b.16,000 C.32,000 D..032

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

32

Explanation:

There cannot be more in a number than the number. Therefore, the answer has to be D, or 32.

Hope this helps! :)

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Question is in picture
notsponge [240]

Answer:

Explanation: hELLO its b

6 0
3 years ago
Calculate the hydronium ion concentration in an aqueous solution with a poh of 4.33 at 25°c.
Jlenok [28]

Taking into account the definition of pH and pOH, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or  hydronium ion H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Definition of pOH</h3>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

<h3>Relationship between pH and pOH</h3>

The following relationship can be established between pH and pOH:

pOH + pH= 14

<h3>Concentration of hydronium ions</h3>

Being pOH= 4.33, pH is calculated as:

pH + 4.33= 14

pH= 14 - 4.33

<u><em>pH= 9.67</em></u>

Replacing in the definition of pH the concentration of hydronium ions is obtained:

- log [H₃O⁺]= 9.67

Solving:

[H₃O⁺]= 10⁻⁹ ⁶⁷

<u><em>[H₃O⁺]= 2.138×10⁻¹⁰ M</em></u>

Finally, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

Learn more about pH and pOH:

brainly.com/question/16032912

brainly.com/question/13557815

#SPJ1

4 0
2 years ago
The volume of a given mass of an ideal gas at constant pressure is
Alenkasestr [34]
Would that be mass times volume?


3 0
3 years ago
Which is the balanced version of the half-reaction below?<br> H2S → S+H+
chubhunter [2.5K]

Answer:

C. H_2S\rightarrow S+2H^++2e^-

Explanation:

Hello there!

In this case, according to the given chemical reaction, it turns out possible to realize there is one sulfur atom on each side of the chemical equation but two hydrogen atoms on the left and one on the right, which means the latter must be balanced in agreement to the law of conservation of mass.

In such a way, by setting a 2 on H⁺, the reaction will be balanced:

H_2S\rightarrow S+2H^+

Now, we count the transfer electrons for sulfur from -2 to 0 as 2e⁻ on the right, which will match with the option C.

H_2S\rightarrow S+2H^++2e^-

Regards!

7 0
3 years ago
Find the average atomic mass for li if 7.5% of li atoms are 6li with a mass of 6.0151223 amu and 92.5% are 7li with a mass of 7.
gtnhenbr [62]

Answer:

6.94 amu

Explanation:

Step 1: Given data

  • Mass of ⁶Li (m⁶Li): 6.0151223 amu
  • Abundance of ⁶Li (ab⁶Li): 7.5% (0.075)
  • Mass of ⁷Li (m⁷Li): 7.0160041 amu
  • Abundance of ⁷Li (ab⁷Li): 92.5% (0.925)

Step 2: Calculate the average atomic mass (aam) of Li

We will use the following expression.

aam = m⁶Li × ab⁶Li + m⁷Li × ab⁷Li

aam = 6.0151223 amu × 0.075 + 7.0160041 amu × 0.925

aam = 6.94 amu

8 0
3 years ago
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