The mass of carbon dioxide produced from the complete combustion of 4.80 x10^-3 g of methane is 0.0132 grams
calculation
write the equation for combustion of methane (CH4)
CH4 + 2O2 → CO2 + 2H2O
find the moles of CH4 used = mass/molar mass
molar mass of CH4 = 12 +(1 x4) = 16 g/mol
moles =( 4.80 x10^-3 g) / 16 g/mol = 3 × 10^-4 moles
by use of mole ratio between Ch4 to CO2 which is 1:1 the moles of CO2 is also = 3 x10^-4 moles
mass of CO2 is therefore = moles x molar mass of Co2
The molar mass of Co2 = 12 +(16 ×2) = 44 g/mol
mass is therefore = (3 ×10^-4 moles) ×44 g/mol = 0.0132 grams
BaCl₂
Ba²⁺ + Cl⁻ = <span>BaCl₂</span>
Answer:
C. It is the ratio of the concentrations of products to the
concentrations of reactants.
Explanation:
Answer:
b.it has a lower density than most liquid do
142,000 Calories
Hope this helps :O
