Question

How many moles are in 1.93x1023 particles of Na3PO4?

Answer 1

Answer:

The answer is 0.32 moles

Explanation:

To find the number of moles given the number of entities we use the formula

$n = \frac{N}{L}$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 1.93 × 10²³ particles

We have

$n = \frac{1.93 \times {10}^{23} }{6.02 \times {10}^{23 } } \\ = 0.320598006...$

We have the final answer as

0.32 moles

Hope this helps you

Answer 2

Answer :

No. of particles of Na₃PO₄ = 1.93×10²³

We have to find number of moles of the given compound$.$

Number of moles cam be found by using this formula :

$\bigstar\:\boxed{\bf{\purple{n=\dfrac{N}{N_A}}}}$

• n denotes number of moles
• N denotes number of particles
• $\sf{N_A}$denotes avogadro's constant

We know that,

• $\bf{N_A}$ = 6.022×10²³

★ Calculation :

➠ n = N/$\sf{N_A}$

➠ n = (1.93×10²³)/(6.022×10²³)

➠ n = 0.32 moles

★ Explore More :

• n = weight / Molar mass
• n = volume / 22.4

Hope It Helps!