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brilliants [131]
2 years ago
9

The perimeter of a “STOP” sign is 100 in. What is the length of each side?

Mathematics
2 answers:
Brums [2.3K]2 years ago
6 0
Each side is 12.5 inches
ASHA 777 [7]2 years ago
3 0

Answer:

12.5 inches

Step-by-step explanation:

Since a stop sign is an octagon, there are 8 sides total. Since the total perimeter is 100 inches, we can divide 100 by 8. 100 inches divided by 8 sides.

This gives us the answer of 12.5 inches.

hope this helped! :)

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7/10 as a percentage
Darya [45]

Answer:

70 percent. good luck. have a great day

5 0
3 years ago
Read 2 more answers
. What is 6 8ths x 5? Draw a model of your choice to help you solve.<br><br> WILL GIVE BRAINIST
professor190 [17]

Answer:

The complete and simplified answer to the question what is 6/8 of 5 is:  

3 3/4

Step-by-step explanation:

You probably know that the number above the fraction line is called the numerator and the number below it is called the denominator. To work out the fraction of any number, we first need to convert that whole number into a fraction as well.

Here's a little tip for you. Any number can be converted to fraction if you use 1 as the denominator: 5/1

So now that we've converted 5 into a fraction, to work out the answer, we put the fraction 6/8 side by side with our new fraction, 5/1 so that we can multiply those two fractions.

That's right, all you need to do is convert the whole number to a fraction and then multiply the numerators and denominators. Let's take a look:

 

6 x 5/ 8 x 1  =  30 /8

In this case, our new fraction can actually be simplified down further. To do that, we need to find the greatest common factor of both numbers.

You can use our handy GCF calculator to work this out yourself if you want to. We already did that, and the GCF of 30 and 8 is 2.

We can now divide both the new numerator and the denominator by 2 to simplify this fraction down to its lowest terms.

30/2 = 15

8/2 = 4

When we put that together, we can see that our complete answer is:  

15/ 4

 

If you now simplifiy the COMPLETE anwser is:

3 3/4

7 0
2 years ago
To cover A rectangle region of her yard penny needs atleast 170.5 square feet of sod. The length of the region is 15.5 feet. Wha
stiks02 [169]
The area needed is at least 170.5 ft².

Let w  =  the width of the rectangular area.
Because the length is 15.5 ft, therefore the calculated area should be at least 170.5 ft². That is
(15.5 ft)*(w ft) ≥ 170.5 ft²
w ≥ 170.5/15.5
w ≥ 11 ft

Answer:  w ≥ 11 ft
7 0
3 years ago
Determine the slope of the line passing through the given points (1,2) and (2,-1)
alex41 [277]
I hope this helps you



slope=y2-y1/x2-x1



slope=2-(-1)/1-2


slope=3/-1


slope= -3
3 0
3 years ago
Read 2 more answers
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)
vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

x^{\frac{2}{3}}+y^{\frac{2}{3}}=4

We have to find the equation of tangent line to the given curve at point (-3\sqrt3,1)

By using implicit differentiation, differentiate w.r.t x

\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0

Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}

Slope of tangent=m=\frac{1}{\sqrt3}

Equation of tangent line with slope m and passing through the point (x_1,y_1) is given by

y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

y-1=\frac{x}{\sqrt3}+3

y=\frac{x}{\sqrt3}+3+1

y=\frac{x}{\sqrt3}+4

This is required equation of tangent line to the given curve at given point.

8 0
3 years ago
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