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3 years ago

Please someone help!

Mathematics

1 answer:

babymother [125]3 years ago

8 0

Answer:

Step-by-step explanation:

tan^-1 (2.1/ 7.2) = 16 .26...

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Suppose that n represents an integer. What expression represents the next larger integer ? the previous integer? the sum of thes

qwelly [4]

Answer:

next expression is n+1,

previous expression is n-1

sum of 3 consecutive integers is 3n

Step-by-step explanation:

Please thank me if u want:)

4 0

3 years ago

The length of a string is L inches. Samantha cuts it into two unequal pieces such that the length of the small piece is 35% of L

skelet666 [1.2K]

Answer:

The shorter piece x = 8.4 in

The longer one y = 15.6 in

Step-by-step explanation:

If we cut a string length L in to unequal pieces we get two pieces

first one with length x and the other one with length y

Let call x the smaller piece, then y = L - x will be the longer one

If x = 35 % then

x = 0,35* L and

y = L - x = L - 0,35*L ⇒ y = 0,65 L ⇒ y = 0.65*24

Now if L = 24 in

x = 0,35*24 ⇒ x = 8.4 in

and

L - x = 0.65*L ⇒ L - x = 0.65*24 y = L - x = 15.6 in

as way of verification you can add the length of the two pieces and find:

8.4 + 15.6 = 24 in

4 0

3 years ago

Which is bigger 0.17meter or 0.165 meter

-BARSIC- [3]

I believe it is 0.165.

5 0

3 years ago

Read 2 more answers

What will be the value of

madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

$\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}$

Then you want to know the value of

$\displaystyle\lim_{n\to\infty}a_n$

if it exists.

To show the limit exists and that $a_n$ converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that $a_1=\sqrt{42}\le\sqrt{49}=7$ . Suppose $a_k\le 7$ . Then $a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7$ . So by induction, $a_n$ is bounded above by 7 for all $n$ .

Monontonicity: We have $a_1=\sqrt{42}$ and $a_2=\sqrt{42+\sqrt{42}}$ . It should be quite clear that $a_2>a_1$ . Suppose $a_k>a_{k-1}$ . Then $a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k$ . So by induction, $a_n$ is monotonically increasing.

Then because $a_n$ is bounded above and strictly increasing, the limit exists. Call it $L$ . Now,

$\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}a_{n-1}=L$

$\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}\sqrt{42+a_{n-1}}=\sqrt{42+\lim_{n\to\infty}a_{n-1}}$

$\implies L=\sqrt{42+L}$

Solve for $L$ :

$L^2=42+L\implies L^2-L-42=(L-7)(L+6)=0\implies L=7$

We omit $L=-6$ because our analysis above showed that $L$ must be positive.

So the value of the infinitely nested radical is 7.

4 0

3 years ago

I’m I right? If not change it for me

dangina [55]

The first and third are correct. They are equal.

The second is incorrect. This is because 1800 meters = 1.8 km (not 18 km). The answer you should have is a "less than sign" because 1.8 km is smaller than 18 km.

To go from meters to kilometers, you move the decimal point 3 spots to the left. This is the same as dividing by 1000.

To go from kilometers to meters, you move the decimal point 3 spots to the right. This is the same as multiplying by 1000.

8 0

3 years ago

Read 2 more answers