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kaheart [24]
2 years ago
5

Students were asked to choose their favorite sport, and 7/9 chose either

Mathematics
1 answer:
alisha [4.7K]2 years ago
8 0
2/9 students chose soccer because if on 7 out of 9 kids picked those two the other 2 don’t matter. then if 5 out of 7 kids chose basketball then only 2 out of the 7 kids are left. therefore the answer being 2/9 or 2/7
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a restaurant owner bought 4 boxes of disposable cups for $145 , with each box containing 1,656 cups. if he wanted to divvy up th
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1104 cups per 1 restaurant

There are FOUR boxes EACH containing 1656 cups, MEANING that you will do 1656 x 4, getting 6624.

You divide this by 6, and TADA!

Hope this helps!
5 0
3 years ago
Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes
saveliy_v [14]

The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2 
we cannot have x equal to zero because the number can be infinite. 
So the LCD here is 10x, so multiply both sides by that to get: 
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8 0
3 years ago
In a group of 60 students, 12 students take Algebra I, 18 students take Algebra II, and 8 students take both subjects. How many
vodomira [7]
Since 8 students take both, that leaves only 4 students who take Algebra I alone.
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b. 38

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4 0
3 years ago
Read 2 more answers
Tori has a bag with 3 blue marbles, 5 red marbles and 1 yellow marble. She chooses a marble at random, returns it to the bag, an
Damm [24]

Answer:

3-    5-   1

^      ^     ^

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Step-by-step explanation:

5 0
3 years ago
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An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the
julia-pushkina [17]

Answer:

The rate of decrease is: 43.2mm^3/min

Step-by-step explanation:

Given

l = 18mm

\frac{dl}{dt} = -0.8mm/min ---- We used minus because the rate is decreasing

Required

Rate of decrease when: l = 18mm

The volume of the cube is:

V = l^3

Differentiate

\frac{dV}{dl} = 3l^2

Make dV the subject

dV = 3l^2 \cdot dl

Divide both sides by dt

\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}

Given that: l = 18mm and \frac{dl}{dt} = -0.8mm/min

\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)

\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min

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<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0
3 years ago
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