A 20-liter container contains 2. 0 moles of oxygen at a pressure of 92 kpa. The average kinetic energy of translation of oxygen

Question

1 year ago

12

molecules in the gas is?

1 answer:

Elodia [21] · Answer 1 · 2024-02-29T07:13:39+03:00

The average kinetic energy of translation of oxygen molecules in the gas is 5.05 × 10⁻²¹

The given data is

n = 2

v = 20

P = 92

K.E = 3 / 2 KbT

= 3 / 2 PV / N

= 3 / 2 Pv / nNa

K.E = 3 / 2 × 9 × 1.013 × 10⁵ × 20 × 10⁻³ / 2 × 6.022 × 10²³

K. E = 5.05 × 10⁻²¹ J

<h3>Average kinetic energy</h3>

The average kinetic energy (K) is equal to one half of the mass of each gas molecule times the RMS speed squared

Hence, the average kinetic energy is 5.05 × 10⁻²¹ J

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