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Rainbow [258]
3 years ago
11

Methane (CH4) is the main component of marsh gas. Heating methane in the presence of sulfur produces carbon disulfide and hydrog

en sulfide as the only products. (a) Write the balanced chemical equation for the reaction of methane and sulfur. (Use the lowest possible coefficients. Include states of matter under SATP conditions in your answer.)(b) Calculate the theoretical yield of carbon disulfide when g of methane is reacted with an equal mass of sulfur.
Chemistry
1 answer:
larisa [96]3 years ago
5 0

Answer:

71.25 g

Explanation:

Methane + Sulfur = Carbon Disulfide + Hydrogen Sulfide

The equation is given as;

CH4 + S --> CS2 + H2S

Upon balancing, we have;

CH4(g) + 4S(s) → CS2(l) + 2H2S(g)

Theoretical yield of carbon disulphide;

Equal masses of 120g

The limiting reactant is sulphur It determines how much of the product is formed.

From the equation;

4 mol of S produces 1 mol of CS2

upon converting to masses using; Mass = number of mol * Molar mass

4 mol of S = 4 * 32

1 mol of CS2 = 76g

128g of S produces 76g of C2, 120g would produce ?

128 = 76

120 = x

x = 120 * 76 / 128

x = 71.25g

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P and Q are two substances such that the melting point of P and the boiling point of Q are the same. If P is a solid at a certai
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Explanation:

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3 years ago
37.2 liters of a gas has a pressure of 362.43 kPa at 46.5 °C. If the pressure increases to
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Answer:

Option A. 25.7 L.

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial volume (V1) = 37.2 L

Initial pressure (P1) = 362.43 kPa

Initial temperature (T1) = 46.5 °C

Final pressure (P2) = 693.9 kPa

Final temperature (T2) = 149.2 °C

Final volume (V2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This can be achieved as shown below:

Temperature (K) = Temperature (°C) + 273

T (K) = T (°C) + 273

Initial temperature (T1) = 46.5 °C

Initial temperature (T1) = 46.5 °C + 273 = 319.5 K.

Final temperature (T2) = 149.2 °C

Final temperature (T2) = 149.2 °C + 273 = 422.2 K.

Step 3:

Determination of the new volume.

This can be obtained by using the general gas equation as shown below:

Initial volume (V1) = 37.2 L

Initial pressure (P1) = 362.43 kPa

Initial temperature (T1) = 319.5 K

Final pressure (P2) = 693.9 kPa

Final temperature (T2) = 422.2 K

Final volume (V2) =.?

P1V1/T1 = P2V2/T2

362.43×37.2/319.5 = 693.9 × V2/422.2

Cross multiply

319.5×693.9×V2 = 362.43×37.2×422.2

Divide both side by 319.5 × 693.9

V2 = (362.43×37.2×422.2)/(319.5×693.9)

V2 = 25.7 L

Therefore, the new volume is 25.7 L.

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