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1 year ago

If a bacteria cannot ferment glucose, why not test its ability to ferment other carbohydrates?

1 answer:

6 0

If a bacteria cannot ferment glucose, then we do not test its ability to ferment other carbohydrates because the glucose is monosaccharides, the bacteria required enzymes that used to ferment glucose.

Bacteria cannot ferment carbohydrates because carbohydrates may include non-reducing sugar like sucrose and lactose, which is disaccharide, that must be cleaved into monosaccharides. Not all, bacteria can do this to may or may not ferment sucrose.

Many microorganism can grow in the base broth without the carbohydrates, but if they can ferment a sugar that is available. It is possible that one bacteria metabolize some sugar but can't work on other.

To learn more about non-reducing sugar here

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Gametes are produced by the process of

kirill [66]

The answer is D meiosis

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Two ice skaters stand facing each other. The first skater has a mass of 100 kg and the second has a mass of 50 kg. They push eac

olga_2 [115]

The second skater accelerates at 6 $m/s^2$ to the right.

Let the first skater be F.

Let the second skater be S.

Given the following data:

Mass of F = 100 kg

Mass of S = 50 kg

Acceleration of F = 3 $m/s^2$

To find the acceleration of the second ice skater, we would apply Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by this formula;

$Force = Mass$ × $acceleration$

Substituting the given values, we have;

$Force = 100$ × $3$

Force = 300 Newton

Note: The same force is acting on the two ice skaters and the second ice skater would be pushed in the opposite direction (right).

Now, we would find the acceleration of the second ice skater:

$Acceleration = \frac{300}{50}$

Acceleration of S = 6  $m/s^2$ 

Therefore, the acceleration of the second ice skater is 6 $m/s^2$ to the right.

Read more here: brainly.com/question/24029674

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3 years ago

What are the indicators of nutritional risk in pregnancy in a client who is of normal weight?

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The indicators of nutritional risk in pregnancy in a client who is of normal weight are; smoker, Twin gestation, and also term delivery 2 years ago . Smokers usually have a nutrient-poor diet and are at risk of continuing the same diet during pregnancy. Multifetal pregnancies require nutrition above the normal requirements for pregnancy.

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What is one of the contributions made to the development of the microscope by Galileo?

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The correct answer is: 3. used math to improve the focus of the lens

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4 years ago

Read 2 more answers

If you examine 100 F₁ plants from the testcross and find that 44 have purple flowers with tall stems and 56 have purple flowers

tatuchka [14]

Answer:

PPTt

Explanation:

Let the gene for flower colour be denoted by P. P is the dominant allele and produces purple colour, p is the recessive allele and produces the recessive colour. Let the gene for stem height be denoted by T. T is the dominant allele and produces tall stem, t is the recessive allele and produces short stem.

A test cross was done which means that one of the parents was homozygous recessive for both the traits i.e. pptt

In the progeny all the flowers had purple colour which is only possible if the test parent was homozygous dominant for the trait i.e. it was PP

PP x pp :

P P

p Pp Pp

As evident, all the flowers will have Pp genotype and hence purple colour.

In the progeny, around half of the flowers had tall stems and half had short stems. This is only possible if the test parent was heterozygous for the trait i.e. it was Tt

Tt X tt :

T t

t Tt tt

As evident, half plants have Tt genotype so they will have tall stems. Half of them have tt genotype hence will have short stems.

Hence, combining the genotype for two traits we obtain the genotype PPTt of the original test pea plant.

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3 years ago