M∠3 + m∠4 = 180° ( RIGHT)
m∠2 + m∠4 + m∠6 = 180° ( RIGHT)
m∠2 + m∠4 = m∠5 ( RIGHT)
m∠1 + m∠2 = 90° (WRONG)
m∠4 + m∠6 = m∠2 (WRONG)
m∠2 + m∠6 = m∠5 (WRONG)
Without the table I will guess 5 is common to all 3 they are proportional
Answer: The answer what you seek is D
Answer:
5400 mi²
Step-by-step explanation:
The area is half the absolute value of the sum of the determinants of the points taken pairwise in some consistent order around the polygon. For a triangle, this sum of determinants can also be written as the determinant of a 3×3 matrix of the coordinates with the third column being 1.
... Area = (1/2)|D|
where D = ...
![\left|\begin{array}{ccc}0&-1&1\\-3&-9&1\\3&-2&1\end{array}\right|=\left|\begin{array}{cc}0&-1\\-3&-9\end{array}\right|+\left|\begin{array}{cc}-3&-9\\3&-2\end{array}\right|+\left|\begin{array}{cc}3&-2\\0&-1\end{array}\right|\\\\=-3+33-3=27](https://tex.z-dn.net/?f=%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%261%5C%5C-3%26-9%261%5C%5C3%26-2%261%5Cend%7Barray%7D%5Cright%7C%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C-3%26-9%5Cend%7Barray%7D%5Cright%7C%2B%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D-3%26-9%5C%5C3%26-2%5Cend%7Barray%7D%5Cright%7C%2B%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D3%26-2%5C%5C0%26-1%5Cend%7Barray%7D%5Cright%7C%5C%5C%5C%5C%3D-3%2B33-3%3D27)
Then the area is (in grid squares) ...
... Area = (1/2)|27| = 13.5 . . . . grid squares
Each grid square is (20 mi)² = 400 mi², so 13.5 grid squares is ...
... 13.5 × 400 mi² = 5400 mi²
Answer:
At time t hours,
D(t) = √(5200t²)
Step-by-step explanation:
Charlies car is travelling at 40 miles/h while andy's car is travelling at 60 miles/h.
Now, distance = speed x time
Thus;
At a time t, the distance, covered by Charlie's car will be;
D1 = 40t
Similarly, At a time t, the distance, covered by Andy's car will be;
D2 = 60t
Using Pythagoras theorem,
D² = (40t)² + (60t)²
D² = 1600t² + 3600t²
D² = 5200t²
D = √(5200t²)