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Liono4ka [1.6K]
4 years ago
7

How many subsets are there of the set N = {1, 42, 65, 12, 31, 27}?

Mathematics
1 answer:
lutik1710 [3]4 years ago
4 0

Answer:

\boxed{ \bold{  \huge{ \boxed{ \sf{64}}}}}

Step-by-step explanation:

If ' n ' is the cardinal number of a set, the number of subsets of a given set can be obtained by using the formula 2ⁿ

Given,

N = { 1 , 42 , 65 , 12 , 31 , 27 }

where n ( total number of elements ) = 6

So, the number of possible subsets of set N :

= 2ⁿ

= 2⁶

= 2 × 2 × 2 × 2 × 2 × 2

= 64

Hope I helped!

Best regards!!

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4(x+2)=4x+8 need help
alisha [4.7K]

Answer:

The answer is all real numbers

Step-by-step explanation:

4(x + 2) = 4x +8

Distribute the 4:

4x + 8 = 4x + 8

Then subtract 4x and 8 from both sides

0 = 0

This statement is true so its all real numbers

3 0
3 years ago
Read 2 more answers
F(x)= 4x^3-8x-2x^6 in standard form
tankabanditka [31]
ANSWER-

2x(2x^2-4-x^5)

EXPLANATION-

GCF is 2 then factor
8 0
3 years ago
HURRY PLEASE I REALLY NEED HELP WITH THIS. ILL GIVE 100 POINTS!!
mash [69]

Answer:

use the app thats what its for lol

6 0
2 years ago
A explanation would help very much
Leni [432]

Answer:

x = 14

y = 40

Step-by-step explanation:

3y+8 = 128

3y = 120

y = 40

45/20=2.25 (scale factor)

5x-25 = 2.25(2x-8)

5x-25 = 4.5x - 18

.5x = 7

x=14

4 0
3 years ago
If possible could you explain how to get the answer if not it is ok.
Softa [21]

Rules of exponents come in hand here.

Multiplication rule: a^m x a^n = a^ m+n

Division rule: a^m / a^n = a^m-n

Negative exponent: a^-m = 1/a^m; 1a^-m =a^m

So it would be (-3)^7+5 / (-3)^-2; (-3)^12 / (-3)^-2; (-3)^12 x (-3)^2; (-3)^14

The answer is (-3)^14. If you multiply it out it is 4,782,969.

3 0
3 years ago
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