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3 years ago

How many subsets are there of the set N = {1, 42, 65, 12, 31, 27}?

Mathematics

1 answer:

lutik1710 [3]3 years ago

4 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{64}}}}}$

Step-by-step explanation:

If ' n ' is the cardinal number of a set, the number of subsets of a given set can be obtained by using the formula 2ⁿ

Given,

N = { 1 , 42 , 65 , 12 , 31 , 27 }

where n ( total number of elements ) = 6

So, the number of possible subsets of set N :

= 2ⁿ

= 2⁶

= 2 × 2 × 2 × 2 × 2 × 2

= 64

Hope I helped!

Best regards!!

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What is the equation 22-2h=-5?

Marrrta [24]

Answer:

h = -9

Step-by-step explanation:

Simplifying

5h + 22 + -2h = -5

Reorder the terms:

22 + 5h + -2h = -5

Combine like terms: 5h + -2h = 3h

22 + 3h = -5

Solving

22 + 3h = -5

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-22' to each side of the equation.

22 + -22 + 3h = -5 + -22

Combine like terms: 22 + -22 = 0

0 + 3h = -5 + -22

3h = -5 + -22

Combine like terms: -5 + -22 = -27

3h = -27

Divide each side by '3'.

h = -9

Simplifying

h = -9

4 0

2 years ago

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

Which expression is the factored form of −1.5w+7.5 ?

prohojiy [21]

Answer:

Step-by-step explanation:

the most that can be factored out is -1.5,

-1.5 * w = -1.5w

-1.5 * -5 = 7.5

-1.5w + 7.5, so it's

-1.5(w-5)

8 0

2 years ago

Sydney purchases a new car for $27,500. The value of the car decreases at rate of 15% each year. In approximately will the $1,25

Pani-rosa [81]

Answer:

Time taken n = 19 years (Approx)

Step-by-step explanation:

Given:

Amount of car P = $27,500

Decrease rate r = 15% = 0.15

Final amount A = $1,254

Find:

Time taken n

Computation:

A = P[1-r]ⁿ

1,254 = 27,500[1-0.15]ⁿ

0.0456 = [0.85]ⁿ

Time taken n = 19 years (Approx)

8 0

2 years ago

Read 2 more answers

Con las cuatro cartas que se muestran en la figura se pueden formar diferentes números. Por ejemplo: 8232 o 3822. ¿Cuántos númer

densk [106]

Answer:

Se pueden formar 9 números pares.

Step-by-step explanation:

Dado que con cuatro cartas se pueden formar diferentes números, como por ejemplo 8232 o 3822, para determinar cuántos números pares de cuatro dígitos y diferentes puedes formar con estas cuatro cartas se debe realizar la siguiente tabla:

8232 - 8322 - 8223 = 2 pares 1 impar

2832 - 2823 - 2382 - 2328 - 2283 - 2238 = 4 pares 2 impares

3822 - 3282 - 3228 = 3 pares

Por lo tanto, se pueden formar 9 números pares.

5 0

2 years ago