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Lera25 [3.4K]
3 years ago
13

Identify the coefficients in the following expression. -7x + 8y - 3z + y - 9

Mathematics
2 answers:
tresset_1 [31]3 years ago
7 0
Coefficients are numerical quantity that are put before multiplying a variable in an expression, eg. 8 in 8x^y.
Therefore, the coefficients are:
-7
8
-3
and -9
Hope this helps!:)
irina1246 [14]3 years ago
5 0
The coefficients are -7, 8, -3, 1, and -9
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-2 1/2 * (1 2/3) = what?
TiliK225 [7]

Answer:

4.16

Step-by-step explanation:

Mixed Number = 4 1/6

Decimal = 4.16

Fraction = 4.1666666

Percentage = 416%

7 0
2 years ago
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What is the sum of (2x - 5y) and (x + y)?
seraphim [82]

Answer:

3x-4y

Step-by-step explanation:

combine like terms. 2x+x=3x.

-5y+y=-4y

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=
BARSIC [14]
<h3>Answer:  -2</h3>

======================================================

Work Shown:

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0
3 years ago
Graph <br> y = 2 x + 3 <br> pls help thx &lt;3
quester [9]
Second one I think...
8 0
2 years ago
Read 2 more answers
What is (9x + 5) - (4x + 3)
xenn [34]
9x+5-4x-3=5x+2. You combine like terms after multiplying by negative sign.
7 0
3 years ago
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