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VikaD [51]
3 years ago
8

. A hat contains 100 coins, where 99 are fair but one is double-headed (always landing Heads). A coin is chosen uniformly at ran

dom. The chosen coin is flipped 7 times, and it lands Heads all 7 times. Given this information, what is the probability that the chosen coin is double-headed?
Mathematics
1 answer:
SOVA2 [1]3 years ago
8 0

Answer:0.565

Step-by-step explanation:

Hat contain 100 coins out of which 99 is fair and one is double headed.

Probability of getting 7 heads is sum of Head through fair coin+heads through biased coin

Probability of getting a head through a fair coin=0.5

P(7 heads)=0.99\times 0.5^7+0.01\times 1

P(Double head |7 heads )=\frac{Probability\ of\ 7\ heads\ and\ double\ headed}{probability\ of\ 7\ heads}

P(Double head |7 heads )=\frac{0.01\times 1}{0.99\times 0.5^7+0.01\times 1}

=\frac{0.01}{0.99\times 0.0078+0.01}=0.565

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Evaluate the expression for the given values of the variables.
vfiekz [6]

Answer:

A

Step-by-step explanation:

Substitute the given values into the expression

2a² + cb

= 2(5)² + 3(11)

= 2(25) + 33

= 50 + 33

= 83 → A

7 0
2 years ago
rob is asked to graph this system of equations : 6 x +2y = 5 y = 3x =2 how many times will they intersect
ella [17]

Answer:

The lines will not intersect.

Step-by-step explanation:

I took the test and this was the correct answer, there isnt a solution.

4 0
3 years ago
Read 2 more answers
Find segment ET. Please and thank you​
Solnce55 [7]

Answer:

x=9

Step-by-step explanation:

Use the intersecting chord theorem:

RE*ET = UE*ES

Substitute values

21 (2x+2) = 30 (x+5)

Expand:

42x+42 = 30x + 150

transpose and simplify

42x-30x = 150 - 42

12x = 108

x = 9

4 0
3 years ago
What is 8 3/4 ÷ 2 7/8 (show ur work)
xxMikexx [17]

Answer:

<em><u>see</u></em><em><u> </u></em><em><u>below</u></em><em><u>:</u></em><em><u>-</u></em>

Step-by-step explanation:

\displaystyle{8 \frac{3}{4} \div 2 \frac{7}{8}  }

  • Convert the mixed fractions into improper fractions.

\displaystyle{ \frac{8 \times 4 + 3}{4} \div  \frac{8 \times 2 + 7}{8}  }

\displaystyle{ \frac{32 + 3}{4}  \div  \frac{16 + 7}{8} }

\displaystyle{ \frac{35}{4} \div  \frac{23}{8}  }

\displaystyle{ \frac{35}{4}  \times  \frac{8}{23} }

\displaystyle{ \frac{35}{ \cancel4}  \times  \frac{ \cancel8 {}^{2} }{23} }

\displaystyle{ \frac{35  \times 2}{23} }

\displaystyle{ \frac{70}{23} }

\displaystyle{3 \frac{1}{23} }

6 0
3 years ago
Read 2 more answers
One number is 7 less than another. If 4 times the smaller number plus 2 times the larger number is 62, find the two numbers.
Nana76 [90]
X=Y-7

4X+2Y=62

4(Y-7)+2Y=62

4Y-28+2Y=62

6Y=62+28

6Y=90

Y=90/6

Y=15
Larger number^

X=15-7=8
Smaller number^
PROOF:
4*8+2*15=62

32+30=62

62=62
Hope this helps.
4 0
3 years ago
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