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2 years ago

What is 3/20-3/45+5/12 in simplest radical form

Mathematics

1 answer:

Veronika [31]2 years ago

7 0

Answer:

-3√5 + 10√3

Hope this helps :)

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Which expression has a value of 8?<br> 8x (5-4)<br> (8 x 5) – 4<br> (8 x 5-4)<br> 8 x 5 - 4

fomenos

8x5-4 is equal to 8 if that means 8 times 5 minus 4

4 0

3 years ago

The Wilsons traveled the 2400 miles of Route 66 from Chicago,IL to Santa Monica, CA. If their total driving time was 50 hours, w

Zolol [24]

Answer:

48 miles per hour

Step-by-step explanation:

If they traveled 2400 miles and the total driving time was 50 hours, divide 2400/50 in order to find how many miles they drove per hour.

4 0

2 years ago

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The cost (c) to hire a dog trainer is varies directly with the amount of time (h) in hours spent training the dog.

NNADVOKAT [17]

Answer:

Part A) The proportional equation is $c=55h$

Part B) 8 hours of training

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Let

c -----> the cost to hire a dog

h ----> the amount of time in hours

The linear equation is equal to

$c=kh$

Sue spent $660 on 12 hours of obedience training for her dog Muffin

Find the value of k (constant of proportionality)

$k=y/x$

substitute the values

$k=660/12=55$

therefore

The linear equation is

$c=55h$

For $c=\$440$

Find the value of h

substitute in the equation and solve for h

$440=55h$

$h=440/55=8\ hours$

5 0

3 years ago

If right I’ll mark brainlest

zubka84 [21]

Answer:

154m^2

Step-by-step explanation:

I hope this helps.

4 0

3 years ago

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

Read 2 more answers