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10 months ago

on the asymptotic behavior of the sample estimates of eigenvalues and eigenvectors of covariance matrices

1 answer:

4 0

A complex mathematical topic, the asymptotic behavior of sequences of random variables, or the behavior of indefinitely long sequences of random variables, has significant ramifications for the statistical analysis of data from large samples.

The asymptotic behavior of the sample estimators of the eigenvalues and eigenvectors of covariance matrices is examined in this claim. This work focuses on limited sample size scenarios where the number of accessible observations is comparable in magnitude to the observation dimension rather than usual high sample-size asymptotic .

Under the presumption that both the sample size and the observation dimension go to infinity while their quotient converges to a positive value, the asymptotic behavior of the conventional sample estimates is examined using methods from random matrix theory.

Closed form asymptotic expressions of these estimators are obtained, demonstrating the inconsistency of the conventional sample estimators in these asymptotic conditions, assuming that an asymptotic eigenvalue splitting condition is satisfied.

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How to graph X = (-1/6) y

jenyasd209 [6]

Answer:

X=(-1/6)y

Step-by-step explanation:

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3 years ago

A garden hose having an internal diameter of 0.740 in. ( 1.8796 cm ) is connected to a lawn sprinkler that consists merely of an

lara31 [8.8K]

Answer:

It will leave the sprinkler at speed of $v_2=613.87m/sec$

Step-by-step explanation:

We have given internal diameter of the garden hose $d_1=0.740in=1.8796cm$

So radius $r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm$

So area $A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2$

Water in the hose has a speed of 4 ft/sec

So $v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)$

Number of holes n = 36

Diameter of each hole $d_2=0.1397cm$

So radius $r_2=0.0698cm$

So area $A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2$

From continuity equation

$A_1v_1=nA_2v_2$

$2.7733\times 121.92=36\times 0.0153\times v_2$

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2 years ago

15=x/4 - 3 how do i solve

zhuklara [117]

Answer: the answer is x=72

Step-by-step explanation:

Step 1: simplify both sides we know 15=x/4 -3 (the x holds a invisible 1)

the equation should look something Like: 15=1/4x-3 then FLIP the equation such as:

1/4x-3=15 then add 3 on both sides so 15+3=18

step 2: our equation is now 1/4x=18 (we see 4 is being divided the opposite of division is multiply) therefor multiply the 18 with 4

18*4=72 which means x=72

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1 year ago

Brian can iron 3 shirts in 5 minutes. If Brian irons at a constant rate, how many shirts can he iron in 30 minutes? WILL GIVE BR

never [62]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

PLEASE HELP QUICK!!! A bowl has 85 pieces of candy. Nineteen children empty the bowl of candy. Some children take 3 pieces, some

Mekhanik [1.2K]

Answer: 3 kids take 3 pieces of candy each

Step-by-step explanation:

Let the number of children that took 3 pieces is x ( total take 3*x pieces of candy)

Number of children that took 5 pieces is y ( total take 5*y pieces of candy)

1 child took 1 piece that actually means that x+y=18 and 3*x+5*y=84.

( Because total number of all kids is 19. We just deduct one kid (Let his name is John) who took only 1 candy. So we have 19-1 =18 kids without John. The similar is with the candies. Total number is 85. We deduct 1 piece which John has taken. )

So we have 2 equations or the system of 2 equations:

1). x+y=18

2). 3*x +5*y=84

Multuply both sides of equation 1) by 3

We have 3*x+3*y=18*3

Deduct 3*y from both sides of this equation

3*x+3*y-3*y=54-3*y

3*x=54-3*y

Substitute 3*x in equation 2). by 54-3*y

2) 54-3*y+5*y=84

2*y=30

y=15 ( kids take 5 pieces of candy each)

Using equation 1) find x

x+15=18

x=3 (kids take 3 pieces of candy each)

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2 years ago