Astronauts are weightless when in orbit in space. are they also weightless during the launch of the station? How about during th
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Answer:
It will take 0.01 s or 10 ms
Solution:
As per the question:
Length of the packet, L = 1,000 bytes =
Distance, d = 2500 km =
Speed of propagation, s =
Transmission rate, R = 2 Mbps
Now,
Propagation time, t can be calculated as:
t = 10 ms
- In general, propagation time, t is given by:
- No, this delay is independent of the length of the packet.
- No, this delay is independent of the rate of transmission.
is the period of orbit.
<u>Explanation: </u>
The equation that is useful in describing satellites motion is Newton form after Kepler's Third Law. The period of the satellite (T) and the average distance to the central body (R) are related as the following equation:
Where,
T is the period of the orbit
R is the average radius of orbit
G is gravitational constant
Here, given data
Substitute the given values, we get T as
Taking square root, we get
The period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.
<h3>What is time period of pendulum?</h3>Pendulum is the body which is pivoted to a point and perform back and forth motion around that point by swinging due to the influence of gravity.
The time period of a pendulum is the time taken by it to complete one cycle of swing left to right and right to left.
It can be given as,
Here, (g) is the gravitational force of Earth and (L) is the length of the pendulum.
A pendulum of length 3.171 m. The acceleration of gravity is 9.832 m/s2. The period at the north pole is,
Thus, the period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.
Learn more about the time period of pendulum here;
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