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3 years ago

The device that demonstrates the presence of static electricity is called a(n) _____.

Physics

2 answers:

galben [10]3 years ago

8 0

<span>The device that demonstrates the presence of static electricity
is called a electroscope .</span>

maks197457 [2]3 years ago

6 0

Answer:

Electroscope

Explanation:

Electroscope is a device which is used to detect the static charge on a body. The most common electroscope is gold leaf electroscope. It consists of a glass jar in which two gold leaves are connected to the conducting rod whic s connected to the a metal disc.

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A snail crawls at a speed of 0.0004 m/s. How long will ot take to climb a garden stick 1.6m high?

tekilochka [14]

4000 seconds

Explanation:

speed = distance / time

0.0004m/s = 1.6m / time

Subject time

time = 1.6 / 0.0004

time = 4000 seconds.

Hope this helps. Mark as brainliest if possible. tks

5 0

3 years ago

A person sitting on a pier observes incoming waves that have a sinusoidal form with a distance of 2.5 m between the crests. Of a

Doss [256]

Answer:

Part(a): The frequency is $\bf{0.2~Hz}$ .

Part(b): The speed of the wave is $\bf{0.5~m/s}$ .

Explanation:

Given:

The distance between the crests of the wave, $d = 2.5~m$ .

The time required for the wave to laps against the pier, $t = 5.0~s$

The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is $\lambda = 2.5~m$ .

Also, the time required for the wave for each laps is the time period of oscillation and it is given by $T = 5.0~s$ .

Part(a):

The relation between the frequency and time period is given by

$\nu = \dfrac{1}{T}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

Substituting the value of $T$ in equation (1), we have

$\nu &=& \dfrac{1}{5.0~s}\\~~~&=& 0.2~Hz$

Part(b):

The relation between the velocity of a wave to its frequency is given by

$v = \nu \lambda~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)$

Substituting the value of $\nu$ and $\lambda$ in equation (2), we have

$v &=& (0.2~Hz)(2.5~m)\\~~~&=& 0.5~m/s$

5 0

3 years ago

A ball is dropped from some height. It bounces off the floor and rebounds with a speed that is one-half the speed it had just be

Arada [10]

Answer:

The correct option is C

Explanation:

According to third equation of motion, v

+2ax

Here, u=0 m/s

a=−g and x=−h

Negative sign indicates downward direction. Displacement and acceleration both are downwards.

So,v=±

2(−g)(−h)

We take minus sign because it is downwards.

v=−

2gh

After bouncing. velocity becomes 80% of v, i.e.,

′

=+0.8

2gh

(positive sign because the direction of ball has reversed after bouncing and is upwards.

Applying third equation of motion again, for u=v

′

, v=0 and a=−g

+2×a×x

Thus,

0=0.64(2gh)+2(−g)x

x=0.64h

3 0

2 years ago

A chair of weight 95.0N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 3

AlladinOne [14]

Answer:

118.4 N

Explanation:

weight of chair, mg = 95 N

Push, F = 39 N

Ф = 37 ° below x axis

Let n be the normal force.

So, by using the diagram and resolve the components of Force F.

n = mg + F SinФ

n = 95 + 39 Sin 37°

n = 95 + 39 x 0.6

n = 118.4 N

Explanation:

7 0

4 years ago

Read 2 more answers

A uniform disk of mass 3.25 kg has a radius of 0.100 m and spins with a frequency of 0.550 rev/s. What is its angular momentum?

shutvik [7]

ANSWER:

0.0562 J

STEP-BY-STEP EXPLANATION:

Angular momentum is expressed in terms of moment of inertia and angular velocity. This is expressed as follows:

$L=I\cdot\omega$

Here, I is the angular momentum and ω is the angular velocity.

Angular momentum is mass time the square of the radius of the object. Moment of inertia for a uniform disk is given as,

$I=\frac{1}{2}m\cdot r^2$

Here, m is the mass of the disk and r is the radius of the disk.

Replacing:

$L=\frac{1}{2}m\cdot r^2\cdot\omega$

Convert the units of angular velocity into rad/s.

$\begin{gathered} \omega=0.55\text{ rev/s}\cdot\frac{2\pi\text{ rad}}{1\text{ rev}} \\ \omega=3.46\text{ rad/s} \end{gathered}$

We replace each data to calculate the angular momentum:

$\begin{gathered} L=\frac{1}{2}\cdot3.25\cdot0.1^2\cdot3.46 \\ L=0.0562 \end{gathered}$

The angular momentum of the uniform disk is 0.0562 J

7 0

1 year ago