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3 years ago

Which of the following has larger in a car or a bicycle ride with reason

Physics

2 answers:

Basile [38]3 years ago

6 0

Answer:Gotta give an example

Explanation:

Xelga [282]3 years ago

4 0

Answer:

bicycle

Explanation:

Regardless of the reason for the crash prevention is the name of the game,and remember all state require cyclist to ride on the roadway to follow the same rules and regulations that's why you ride a bike that fits you if its to big its harder to control

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A lumberjack (mass = 98 kg) is standing at rest on one end of a floating log (mass = 290 kg) that is also at rest. The lumberjac

Dafna11 [192]

Answer:

a)V= - 1.11 m/s

b)V= 0.833 m/s

Explanation:

Given that

M (Mass of lumberjack)= 98 kg

Final velocity of lumberjack ,V₁= 3.3 m/s

m (Mass of log) = 290 kg

There is no any external force that is why linear momentum will be conserved

Pi=Pf

initially both are at rest so Pi=0 ( P = m v)

Lets take speed of log is V

0= M V₁ + m V

V = - M V₁ / m

V= - 98 x 3.3 / 290

V= - 1.11 m/s

Now again from linear momentum conservation

(m + M )V =M V₁

V= M V₁(m+M)

By putting the values

V= 98 x 3.3/ (98 + 290 )

V= 0.833 m/s

3 0

3 years ago

On a different planet, a ball is fired straight upwards from the ground with an initial speed of 100 m/s. At the same instant, a

tensa zangetsu [6.8K]

Answer:

g = 25 m/s²

Explanation:

Since, the balls meet at the exact instant when upward thrown ball reaches its maximum point. Therefore, applying 1st equation of motion to it, we get:

Vf₁ = Vi₁ + gt

where,

g = -g (for upward motion) = acceleration due to gravity at that planet = ?

t = time

Vf₁ = Final Velocity of Upward Thrown ball = 0 m/s (ball stops at highest point)

Vi₁ = Initial Velocity of Upward Thrown Ball = 100 m/s

Therefore,

0 m/s = 100 m/s - gt

gt = 100 m/s ------------- equation 1

Now, applying 3rd equation of motion for the height covered:

2(-g)h₁ = Vf₁² - Vi₁²

h₁ = 10000/2g

Now, we apply 2nd equation of motion to second ball moving downward:

h₂ = Vi₂t + (0.5)gt²

where,

h₂ = height covered by second ball at the time of meeting

Vi₂ = initial velocity of second ball = 0 m/s (since, it starts from rest)

Therefore,

h₂ = (0)(t) + (0.5)gt²

h₂ = (0.5)gt²

Now, it is clear from the given condition, that when the two balls meet, the sum of distance covered by both the balls will be equal to 400 m. Therefore,

h₁ + h₂ = 400 m

using values:

10000/2g + (0.5)gt² = 400

10000 + g²t² = (400)(2g)

using equation 1:

10000 + (100)² = 800g

g = 20000/800

g = 25 m/s²

7 0

4 years ago

Explain how all three of Newton’s Laws of Motion apply to weightlifting.

Lubov Fominskaja [6]

Answer:

Newton's first law, an object will stay at rest only if there are no external forces acting on the object or if the net external force acting on the object is zero. Since the barbell is at rest (not moving), the net external force acting on it must be zero

Newton's Second Law of Motion via the equation f = ma, or put differently, force is equal to mass multiplied by acceleration. To generate more force, we must either increase mass or acceleration (or both)

Newton's Third Law of Motion is known as the equal and opposite reaction principle

7 0

4 years ago

People who are exceptionally tall (like seven feet and over) often have a disorder that causes them to keep growing past the age

AleksandrR [38]

Answer:

C is the answer

Explanation:

The pituitary gland also known as the Master gland controls and regulates secretion of most hormones, when taller people usually grow past expected height this is normally due to the Pituitary gland not properly regulating and it secretes too many growth hormones causing "gigantism."

6 0

3 years ago

A horse walks along a straight path. it travels 3 in one second, 4 m in the next second, and 5 m in the third second. describe t

Temka [501]

Answer: The horse is moving with a uniform acceleration

Explanation:

According to the described situation, we are dealing with a constant acceleration (also called uniform acceleration), since the horse's velocity is changingn by a constant rate.

Let's prove it:

Firstly we are told the horse follows a straight path. In addition we are given its velocity:

3 m/s, then 4 m/s and 5 m/s

Since acceleration $a$ is defined as the change of velocity in time we can calculate it:

$a\frac{4 m/s-3 m/s}{1 s}=1m/s^{2}$ This is the horse's constant acceleration

3 0

3 years ago

Which of the following has larger in a car or a bicycle ride with reason ​

Which of the following has larger in a car or a bicycle ride with reason