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Butoxors [25]
3 years ago
5

Draw the model of an atom with an atomic number of 7 and a mass number of 15. How many valence electrons are in this atom.

Physics
1 answer:
o-na [289]3 years ago
7 0

Answer:

There are 5 valence electrons

Explanation:

Valence electrons are electrons found in the outermost shell of an atom.

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A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, wha
Alborosie

Answer:

v = 70.95 \ m/s.

Explanation:

Given data:

Mass of the man, m = 59 \ kg

Total mechanical energy, E_{i} = 150,023 \ \rm J

Height, h = 2.6 \ m

Suppose there is no external force acting on the man. In this situation, the total mechanical energy (kinetic + potential) will remain steady.

Let the speed of the man at 2.6 m be <em>v</em>.

Thus,

E_{i} = E_{f}

E_{i} = \frac{1}{2}mv^{2} + mgh

150023 = 0.5 \times 59 \times v^{2} + 59 \times 9.80 \times 2.6

\Rightarrow \ v = 70.95 \ m/s.

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3 years ago
How do you spell hard water in three letters.
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Ice, which is the solid state of water, the liquid
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Why did Thomson observe two glowing dots when he put neon gas into a<br> cathode-ray tube?
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Answer:

Electrons accelerated to high velocities travel in straight lines through an empty cathode ray tube and strike the glass wall of the tube, causing excited atoms to fluoresce or glow.

7 0
3 years ago
A scientist would use a balance to measure
GrogVix [38]
Answer is B

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4 years ago
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4. A 70.0 kg boy and a 45.0 kg girl use an elastic rope while engaged in a tug-of-war on an icy,
marta [7]

Answer:

a_1 = 1.446m/s^2

Explanation:

Given

m_1 = 70.0kg -- Mass of the boy

m_2 = 45.0kg -- Mass of the girl

a_2 = 2.25m/s^2 -- Acceleration of the girl towards the boy

Required

Determine the acceleration of the boy towards the girl (a_1)

From the question, we understand that the surface is frictionless. This implies that the system is internal and the relationship between the given and required parameters is:

m_1 * a_1 = m_2 * a_2

Substitute values for m_1, m_2 and a_2

70.0 * a_1 = 45.0 * 2.25

Make a_1 the subject

\frac{70.0 * a_1}{70.0} = \frac{45.0 * 2.25}{70.0}

a_1 = \frac{45.0 * 2.25}{70.0}

a_1 = \frac{101.25}{70.0}

a_1 = 1.446m/s^2

<em>Hence, the acceleration of the boy towards the girl is 1.446m/s^2</em>

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3 years ago
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