5 boys were to carry a load of 2½kg. They shared the load equally. What is the weight of load carried by each boy?

Mathematics

2 answers:

Nataly_w [17]1 year ago

8 0

Answer:

0.5 or 1/2

Step-by-step explanation:

rhe total load is 2.5. so when we divide it by 5 we get 0.5 or 1/2

therefore each boy carry 0.5 weight of load

mr Goodwill [35]1 year ago

5 0

Answer:

1/2 or 0.5 kg

Step-by-step explanation:

This is a division problem.

See attached.

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Im just trying to see if this answer is correct could someone check

Musya8 [376]

I think it’s correct, Your probably correct

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2 years ago

Twenty students choose a piece of fruit from a list of 4 fruits: apple banana grape and pear. The theoretical probability that a

Over [174]

Answer:

Significant difference of 0.20

Step-by-step explanation:

No of student = 20

No of fruits available =4

EAch student is independent of the other.

Hence theoretical probability that a student will choose a banana is=1/4=0.25.

But actual experiments showed that only 1 student selected banana out of 20

Experimental probability that a student will choose a banana is.=1/20 =0.05

The difference between the two = 0.25-0.05 = 0.20

Thus there is a significant difference between Experimental probability that a student will choose a banana and theorical probability that a student will choose a banana

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3 years ago

Read 2 more answers

A factory makes car batteries. The probability that a battery is defective is 1/14. If 400 batteries are tested, about how many

Rufina [12.5K]

Answer:

28.6, that is, about 29 are expected to be defective

Step-by-step explanation:

For each battery, there are only two possible outcomes. Either it is defective, or it is not. The probability of a battery being defective is independent of other betteries. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$