Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
If there are 60 people waiting for a river raft ride. Each raft holds
15 people. how Silvia's work can be used to find the number
of rafts needed is: total number of people/Number of people holded by each raft.
<h3>
Number of rafts needed</h3>
Using this formula
There are 136 people waiting for a river raft ride each raft holds 8 people.
Number of rafts needed=Number of people/Capacity of raft
Where:
Number of people = 60
Capacity of raft = 15 people
Let plug in the formula
Number of rafts needed=60/15
Number of rafts needed=4 rafts needed
Therefore if raft holds 15 people. how Silvia's work can be used to find the number of rafts needed is: total number of people/<em>Number </em>of people holded by each raft.
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Answer2 i would say bc it has the lest so it is ez to react
Step-by-step explanation:
0 if the price of each ride is 42.50 you only have enough to get admission into the fair.
