Find the gcf of 12, 18, and 84

Mathematics

2 answers:

Lady_Fox [76]3 years ago

8 0

Answer: 6 is the GCF

Westkost [7]3 years ago

4 0

Greatest Common Factor of 12,18,84.

Factors of 12:1,2,3,4,6,12
Factors of 18:1,2,3,6,9,18
Factors of 84:1,2,3,4,6,7, 12,14,21,28 42,84

The Greatest Common Factor (GCF) of all those three factors is 6.

The Greatest Common Factor is the greatest Factor in all the numbers. In this set, 12,84,84, 6 is the greatest, making it the Greatest Common Factor.

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A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago

3-(x-1)=-1-(5-x) pls help

Alika [10]

Answer:

$- 3(x - 1) = - 1(5 - x) \\ \\ 3 - x + 1 = - 5 + x \\ \\ - x - x = - 5 - 3 - 1 \\ \\ - 2x = - 5 - 3 - 1 \\ \\ - 2x = - 9 \\ \\ x = \frac{ - 9}{ - 2} \\ \\ x = 4.5$