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wariber [46]
1 year ago
14

A current is applied to two electrolytic cells in series. In the first, silver is deposited; in the second, a zinc electrode is

consumed.How much Ag is plated out if 1.2 g of Zn dissolves?
Chemistry
1 answer:
vitfil [10]1 year ago
6 0

The amount of Ag plated out if 1.2 g of Zn dissolves is 3.959 g .

Given ,

A current is applied to two electrolytic cells in series .

In the first ,silver is deposited and in the second a zinc electrode is consumed .

the reactions involving are ;

Ag+ (aq) + e = Ag

Zn = Zn2+ (aq) +2e

thus the resultant equation is ,

2Ag+ (aq) +Zn = 2Ag + Zn2+

Thus for every mole of Zn dissolves , there is 2 moles of Ag is formed .

65.38 g of Zn contains = 1 moles

1.2 g of Zn contains = 1.2/65.38 =0.01835 moles

for every 1 mole of Zn dissolves there is 2 moles of Ag formed .

Thus the amount of Ag formed in moles =2(O.01835) =0.0367 Moles

1 mole of Ag contains = 107.86g

0.0367 moles of Ag contains = 107.86 (0.0367) =3.959 g of Ag

Hence ,the amount of Ag plated out if 1.2 g of Zn dissolves is 3.959 g .

Learn more about electrolytic cell here:

brainly.com/question/19854746

#SPJ4

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Answer:

chemical substances being held together by attraction of atoms to each other through sharing, as well as exchanging, of electrons -or electrostatic forces.

Explanation:

I hope this helps

5 0
3 years ago
Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i
Leno4ka [110]

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

3 0
3 years ago
Which of the following is true in regard to ions? A. A cation will hold a positive charge if it gains one or more electrons. B.
tigry1 [53]

Answer:

B. An ionized atom has a number of protons that is unequal to the number of electrons.

Explanation:

For a neutral atom , the number of proton and electron is equal. An ionized atom has either loss or gain electron, thereby making the number of proton and electron unequal. The answer B is true because an ionized atom has either loss or gain electron to make the number of electron and proton unequal.

Option A is incorrect because a cations holds a positive charge when it loss one or more electron not when it gains one or more electron(s). Anions possess negative charge for gaining electron(s).

Option C is not true because ions can also carry negative charges and they are called anions.

Option D is false because losing one or more electron will turn an atom to a cations.

7 0
3 years ago
If you flow a solution of Mg CO3-- in water over a Cation resin, what will be in the outlet stream leaving the bed
vodka [1.7K]

In a a cation-exchange resin, the outlet stream leaving the bed will contain H^{+} and CO_3 ^{2-}.

<h3>What is cation-exchange resin?</h3>
  • A resin or polymer that serves as a medium for ion exchange is known as an ion-exchange resin or cation-exchange resin.
  • It is an insoluble matrix (or support structure) made from an organic polymer substrate, typically appearing as tiny (0.25-1.43 mm radius) microbeads that are white or yellowish in color.
  • The process is known as cation-exchange resin because the beads are often porous, providing a wide surface area on and inside them where the trapping of ions takes place along with the concomitant release of other ions.
  • cation-exchange resin comes in many different varieties. Polystyrene sulfonate is the main ingredient in most commercial resins. Many diverse separation, purification, and decontamination techniques use cation-exchange resin.
  • The most typical examples are water filtration and water softening.

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8 0
2 years ago
Rank from most conductive to least conductive: AlCl3, C6H12O6, KBr, C3H7OOH ??
dexar [7]
One needs to rank from the most conductive to the least conductive among the formulas that are given in the question. The ranking will be as given below.
<span>1. AlCl3
2. KBr
3. C3H7OOH
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</span>
I hope that this is the answer that you were looking for and the answer has actually come to your desired help.
3 0
3 years ago
Read 2 more answers
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