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Masteriza [31]
4 years ago
12

How are mass and volumes alike?

Chemistry
1 answer:
AlladinOne [14]4 years ago
3 0
Kind of this is probably wrong Mass weight of solid, volume weight of liquid?
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After an afternoon party, a small cooler full of ice is dumped onto the hot ground and melts. If the cooler contained 6.60 kg of
gtnhenbr [62]

Answer:

The quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

Explanation:

Latent heat of fusion  is the heat absorbed by a unit mass of a given solid at its melting point that completely converts the solid to a liquid at the same temperature. Its unit is Joules/kg or Joules/g.

1 calorie = 4.184 Joules

Therefore , 80.0 cal/g = 80.0 cal/g * 4.184 J/cal = 334.72 J/g

1 g = 0.001 kg; Heat of fusion in J/kg = 334.72 J/g * 1g /0.001 kg = 3.35 * 10⁵ J/kg

Quantity of heat, Q = mass * latent heat of fusion of ice

quantity of heat required = 6.60 kg * 3.35 * 10⁵ J/kg

Quantity of heat required = 2.21 * 10⁶ J

Therefore, the quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

5 0
3 years ago
How many moles are in 5g of Na2CO3? <br>a) 0.047<br>b) 1<br>c) 2<br>d)21.2​
stepladder [879]

Answer:

0.047

Explanation:

Data : 5g , Na2CO3

Formula:

Molecular mass of Na2Co3 = no.of atomic mass x no. of atom

moles = mass÷ molecular mass

molecular mass = 2(23)+1(12)+3(16)

=106amu

moles = 5÷106

= 0.047 Ans:

5 0
3 years ago
|
lilavasa [31]

1.66 M is the concentration of the chemist's working solution.

<h3>What is molarity?</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

In this case, we have a solution of Zn(NO₃)₂.

The chemist wants to prepare a dilute solution of this reactant.

The stock solution of the nitrate has a concentration of 4.93 M, and he wants to prepare 620 mL of a more dilute concentration of the same solution. He adds 210 mL of the stock and completes it with water until it reaches 620 mL.

We want to know the concentration of this diluted solution.

As we are working with the same solution, we can assume that the moles of the stock solution will be conserved in the diluted solution so:

n_1= n_2  (1)

and we also know that:

n = M x V_2

If we replace this expression in (1) we have:

M_1 x V_1= M_2 x V_2

Where 1, would be the stock solution and 2, the solution we want to prepare.

So, we already know the concentration and volume used of the stock solution and the desired volume of the diluted one, therefore, all we have to do is replace the given data in (2) and solve for the concentration which is M_2:

4.93 x 210 =  620 xM_2

M_2 = 1.66 M

This is the concentration of the solution prepared.

Learn more about molarity here:

brainly.com/question/19517011

#SPJ1

6 0
2 years ago
According to rounding rules for addition the sum of 27.1, 34.538, and 37.68 is
Katena32 [7]
The answer should be...99.318!
5 0
3 years ago
What volume of a 0.00945-M solution of potassium hydroxicce would be required to titrae 50.00mL of a sample of acid rain with a
Zepler [3.9K]

<u>Answer:</u> The volume of HBr solution required is 130.16 mL

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH

We are given:

n_1=2\\M_1=123\times 10^{-4}M=0.0123M\\V_1=50mL\\n_2=1\\M_2=0.00945M\\V_2=?mL

Putting values in above equation, we get:

2\times 0.0123\times 50=1\times 0.00945\times V_2\\\\V_2=130.16mL

Hence, the volume of KOH solution required is 130.16 mL

5 0
4 years ago
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