Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
Answer:
$2.72
Step-by-step explanation:
The increase from last week is the fraction ...
(new price)/(old price) -1 = (1.82/1.65) -1 = 17/165
so the amount of increase Sally will pay this week is ...
17/165×$26.40 = $2.72
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<em>Comment on the working</em>
We could work this several ways. Perhaps most straightforward would be to determine how many gallons Sally bought last week, and multiply that by the change in price. Or, the number of gallons could be multiplied by the new price per gallon and the difference from the old purchase amount found.
If you look at the numbers, you see that we have effectively done it the first way. The change in price is $0.17 per gallon, and the number of gallons Sally bought is $26.40/$1.65.
<u>Answer:
</u>
The complete factorization of
are 4(x-3y)(x+3y)
<u>Solution:</u>
Given Data:

Take common value in all the three term.so we take 4 as common term in the above expression

Now factorize the expression 
Find the two numbers, whose product should be 9 and sum should be -6.
-3,-3 are the numbers which satisfy the above condition.
When we add -3-3=Sum is 6
Product of -3
-3= 9
-3 , -3 satisfies the condition.
So the expression will become as
= 
Take the common term
x(x-3y)+3y(x-3y)
(x-3y)(x+3y)
hence the complete factorization of
are 4(x-3y)(x+3y)
Answer: 5 packages of invitations and 6 packages of stamps.
Step-by-step: