Answer:
assuming this is a rectangle:
VW=31
WX=19
YW=36.36
ZX=18.18
VX=36.36
Step-by-step explanation:
VW=VX
VW=31
WX=VX
WX=19
YW^2=19^2+31^2
YW^2=361+961
YW^2=1322
YW=36.36
ZX=1/2VX
ZX=18.18
VX=YW
VX=36.36
Answer:
The probability that a student in this survey says something other than that he or she needs a vacation is:
= 58%.
Step-by-step explanation:
The probability of the teens at the local high school in Oregon who said that they needed a vacation = 42%,
Therefore, the probability that a student in the same survey says something other than that he or she needs a vacation must be 58% (100% - 42%).
Probability calculates the frequency of the occurrences of an event.
Let , side lawn is a.
Area of boundary is :

Now, total cost is given by :

Area left is :

Price to empty space with turfs is :

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.
Answer:
f(u +6) = u
Step-by-step explanation:
Put (u+6) in place of t and simplify:
f(u+6) = (u+6) -6
f(u+6) = u
You work 50 -40 = 10 extra hours per week but get paid for 1.5 times that, or 15 extra hours. In all, you're paid for 40 +15 = 55 hours per week.
.. (55 h/wk)*(4 wk/mo)*($16/h) = $3520/mo
Your gross pay for the month (4 weeks) will be $3,520.