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DiKsa [7]
1 year ago
8

D3 Find two numbers between 100 and 150 that have a HCF of 22.

Mathematics
1 answer:
vesna_86 [32]1 year ago
4 0

The first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132

<h3>Highest common factors</h3>

The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

According to the question, we are to find two numbers between 100 and

150 that have a HCF of 22.

In order to do that we will<u> multiply 22 by the values 5 and 6</u>

First number = 22 * 5 = 10

Second number = 22 * 6 = 132

Hence the first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132

Learn more on HCF here; brainly.com/question/21504246

#SPJ1

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a) The best estimator for the population mean is given by the sample mean \hat \mu = \bar X = 5.70

b) The 99% confidence interval would be given by (4.969;6.431)    

c) We are 99% confident that the true mean for th number of gallons of gasoline  sold to his customers is between 4.969 and 6.431.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.9 represent the population standard deviation

n=45 represent the sample size  

2) Part a

The best estimator for the population mean is given by the sample mean \hat \mu = \bar X = 5.70

3) Part b. Develop a 99 percent confidence interval for the population mean.

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

5.7-2.58\frac{1.9}{\sqrt{45}}=4.969    

5.7+2.58\frac{1.9}{\sqrt{45}}=6.431

So on this case the 99% confidence interval would be given by (4.969;6.431)    

4) Part c. Interpret the meaning of part (b).

On this case we can say this: We are 99% confident that the true mean for th number of gallons of gasoline  sold to his customers is between 4.969 and 6.431.

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