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4 years ago

What is the ordered pair

Mathematics

2 answers:

neonofarm [45]4 years ago

8 0

D. (0.-5)
-5<6(0)-4
-5<0-4
-5<-4

frutty [35]4 years ago

6 0

I think it would be: (0,4), because that is where the inequality meets on the graph.

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Marcy spent 8 minutes on the phone while routing 4 phone calls. In all, how many phone calls does Marcy have to route to spend a

joja [24]

Answer: Marcy will need to route 10 calls to spend a total of 20 mintes on the phone.

Step-by-step explanation: 1 call = 2 minutes.

5 0

3 years ago

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a student usually saves $45 a month. He would like to reach a goal of saving $700 in 12 months. The student writes the equation

serg [7]

Answer:

in this case, x is the amount more he needs to save per month

350=12(x+20)

distribute

350=12x+240

minus 240 both sides

110=12x

divide both sides by 12

9.166666=x

needs to save about $9.17 more per month or 29.17 permonth

Step-by-step explanation:

sorry if its wrong i tried and maybe i could get brainliest?

3 0

3 years ago

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he time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the a

Eva8 [605]

Answer:

The answer is below

Step-by-step explanation:

The time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the answers to 3 decimal places.

(a) What is the probability that more than three aircraft arrive within an hour?

(b) If 30 separate one-hour intervals are chosen, what Is the probability that no interval contains more than three arrivals?

(c) Determine the length of an interval of time (in hours) such that the probability that no arrivals occur during the interval is 0.1.

Solution:

a) A poisson distribution is given by the formula:

$P(X=x)=\frac{e^{-\lambda }\lambda^x}{x!}$

λ = 1 hour

Therefore:

P(X > 3) = 1 - P(X < 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(x = 3)]

$P(X=0)=\frac{e^{-1}*1^0}{0!}=0.3679$

$P(X=1)=\frac{e^{-1}*1^1}{1!}=0.3679$

$P(X=2)=\frac{e^{-1}*1^2}{2!}=0.1839$

$P(X=3)=\frac{e^{-1}*1^3}{3!}=0.0613$

P(X > 3) = 1 - [0.3679+0.3679 + 0.1839 + 0.0613] = 0.019

b) Assuming 30 1 hour intervals, hence:

$P(X \leq 3)^{30}=[1-P(X\geq 30)]^{30}=(1-0.019)^{30}=0.5624$

c) mean = 1 hour

mean = 1 / λ

1 = 1 / λ

λ = 1

The cumulative distribution function of a continuous variable is:

$F(x)=1-e^{-\lambda x}$

$0.1=1-F(x)\\\\0.1=1-(1-e^{- x})\\\\0.1=e^{- x}\\\\-x=ln(0.1)\\\\-x = -2.3\\\\x=2.3\ hours$

4 0

3 years ago

-2 5/22 as a decimal

AURORKA [14]

-2. 227273 thats it

just divide 5/22 dividing

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3 years ago

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Spencer spent four hours doing chores over the weekend. If he spent 2/3 of an hour for each chore how many chores did he do?

Nadya [2.5K]

6 chores (because 4 hours is 240 minutes and 2/3 of an hour is 40 minutes, so you would divide them. Then you would get 240 divided by 40 and the answer would be 6. So Spencer would have done 6 chores)

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3 years ago