Answer:
75%
Step-by-step explanation:
Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
Please give me Brainliest
Answer:
7
Step-by-step explanation:
2^3 • 2^7 = 2^10
When multiplying exponents, the exponents add up together. In other words, just subtract 10-3 = 7 that would be your missing exponent!
Hope this helps, good luck!
Answer:
He put 19 cards into each pile.
Step-by-step explanation:
76 cards in total
piles are qbs, wide receivers, tackles, and line backers = 4 piles
"use division"
so 76 divided by 4 equals 19.