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Wewaii [24]
2 years ago
10

NiCole Spent 15% of her day doing homework. How many hours did she spend on her homework?

Mathematics
1 answer:
Whitepunk [10]2 years ago
4 0

Answer:

4 hour of her day

Step-by-step explanation:

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If you cut a right rectangular prism parallel to its base, apply ink to the cross section, and stamp it on a sheet of paper, whi
kondor19780726 [428]
It would be a square
7 0
3 years ago
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Jessica has two strings. The first string measures 80 centimeters, and the second string measures 64 centimeters. She wants to c
nikdorinn [45]

Answer:

The highest common denominator between 80 and 64 is 16. This means no string can be cut longer than 16 inches for them all to have the same length.

Step-by-step explanation:

4 0
3 years ago
!!Plz urgent help!!
Firdavs [7]

Answer:

890 beads can be fitted in the triangular prism.

Step-by-step explanation:

If we can fill the spherical beads completely in the triangular prism,

Volume of the triangular prism = Volume of the spherical beads

Volume of triangular prism = Area of the triangular base × Height

From the picture attached,

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height})

                                             = \frac{1}{2}(AB)(BC)

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

(13)² = 5² + BC²

169 = 25 + BC²

BC² = 144

BC = 12

Area of the triangular base = \frac{1}{2}(5)(12)

                                             = 30 cm²

Height of the triangular prism = 18 cm

Volume of the triangular prism = 30 × 18

                                                   = 540 cm³

Volume of one spherical bead = \frac{4}{3}\pi r^{3}

                                                   = \frac{4}{3}\pi (0.525)^{3}

                                                   = 0.606 cm³

Let there are 'n' beads in the triangular prism,

Volume of 'n' beads = Volume of the prism

540 = 0.606n

n = 890.90

n ≈ 890

Therefore, 890 beads can be fitted in the triangular prism.

3 0
2 years ago
Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt
liubo4ka [24]

Answer:

x=3

y=-4

Step-by-step explanation:

4x+5y=-8 ----------- (1)

-4x-4y=4 -----------(2)

Adding equation (1) and (2)

4x+5y-4x-4y=-8+4

y=-4

Substitute y=-4 in equation (1) or (2)

4x+5(-4)=-8

4x-20=-8\\4x=-8+20\\4x=12\\x=3

8 0
3 years ago
What is the value of "c" in the following quadratic? (Make sure the equation is in
garri49 [273]

               \rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}

           <em>What is the value of c in the quadratic </em>\large\text{$x^2+28=-11x$}?

          \rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

           Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding \large\textit{11x} on both sides:-

\large\text{$x^2+28-11x=0$}

We can switch the order of 28 and -11x:-

\large\text{$x^2-11x+28=0$}

  Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

  •  \large\text{$ax^2+bx+c=0$}

Now we can just write our <u>quadratic</u> here:-

  • \large\text{$x^2-11x+28=0$}

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

   

Henceforth, we conclude that the value of "c" in the given quadratic is:-

 \Large\textbf{28}\Large\checkmark

<h3>         Good luck with your studies.</h3>

        \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}    

5 0
2 years ago
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