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taurus [48]
3 years ago
14

Show work please do

Mathematics
1 answer:
quester [9]3 years ago
6 0
Here is your answer! I hope this helps.

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Kyle drew three line segments with lengths: 2/4 inch 2/3inch, and 2/6 inch list the fractions in order from least to greatest
Sati [7]
----------------------------------------------------------------
Method 1
 ----------------------------------------------------------------
Since the numerators are the same, the smaller the denominators, the greater the fraction is.

Arranging from the least to the greatest
\dfrac{2}{6} \ , \ \dfrac{2}{4} \ , \ \dfrac{2}{3}


----------------------------------------------------------------
Method 2
----------------------------------------------------------------
Lets change all to the same denominators 

\dfrac{2}{4}  =  \dfrac{2 \times 3}{4 \times 3}  =  \dfrac{6}{12}

\dfrac{2}{3}  =  \dfrac{2 \times 4}{3 \times 4}  =  \dfrac{8}{12}

\dfrac{2}{6}  =  \dfrac{2 \times 2}{6 \times 2}  =  \dfrac{4}{12}

Now that all the denominators are the same, we can arrange the fractions by comparing the numerators. The bigger the numerators, the greater the fraction.

Arranging from the least to the greatest
\dfrac{2}{6} \  , \   \dfrac{2}{4}  \ , \   \dfrac{2}{3}
3 0
4 years ago
Read 2 more answers
In a large population, 82% of the households have cable tv. A simple random sample of 225 households is to be contacted and the
anzhelika [568]

Answer:

The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.82, n = 225.

So

\mu = 0.82

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.82*0.18}{225}} = 0.0256

The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.

7 0
3 years ago
Read 2 more answers
10 The table shows the cost of blueberries at a local farmer's
egoroff_w [7]

Answer:

This question needs rephrasing. It makes no sense.

Step-by-step explanation:

5 0
3 years ago
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
What is y(x)+ab-5 I don’t get the problem
diamong [38]

Answer:

ab+xy−5

Step-by-step explanation:

yx+ab−5  = xy+ab+−5

Simplify-

ab+xy−5

6 0
3 years ago
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