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klasskru [66]
3 years ago
6

A 10 kg box accelerates for at a rate of 12 miles per second what is the force acting on the box

Physics
1 answer:
lions [1.4K]3 years ago
7 0

193080N

Explanation:

Given parameters:

Mass of the box = 10kg

Acceleration = 12miles per second

Unknown:

Force on the box = ?

Solution:

The force acting on the box is function of the mass and acceleration of the box.

  Force = mass x acceleration

   Now we need to convert the given acceleration to m/s

     1000m = 1km

      1.609km = 1miles

    \frac{12 miles }{seconds } x \frac{1.609km}{1miles} x \frac{1000}{1km}

      = 19308m/s

 Force on box = 10 x 19308 = 193080N

Learn more:

Force problems brainly.com/question/4033012

#learnwithBrainly

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A businesswoman is rushing out of a hotel through a revolving door with a force of 80 N applied at the edge of the 3 m wide door
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Answer:

Explanation:

Given

Force applied F=80\ N

Door is d=3\ m wide

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3 years ago
5. The net external force on a rock of mass 4.2 kg is 8.0 N forward. Find the acceleration of the rock.
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Answer:

1.904

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6 0
2 years ago
While the negatively charged rod is near the disk without touching it, a hand briefly touches the end of the post. Then the nega
Paraphin [41]

Answer:

that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

Explanation:

Let us carefully analyze the situation, when the bar is facing the index post a load of equal magnitude, but opposite sign on its surface, these two charges are in balance; When the hand touches the pole, it creates a path to the ground where the charges that were induced on the pole can be balanced with the charge coming from the ground, leaving a zero charge on the pole.

 

   Now if the hand is removed, there can be no exchange of charges with the earth. When the bar is removed, the induced loads are redistributed in the post, but the excess loads that came from the earth that have the same value and are of a sign opposite to the induced ones remain, you want to sign that they are of the same sign as the charges of the bar.

   In summary, after the process, the post has a load of equal magnitude and sign (negative) that of the bar.

   If we assume that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

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Because so little can be found of the first rocks to form on
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Answer:

B is the answer

Explanation:

0-/-<

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