Answer:
Explanation:
An information contains
25Hz and 75Hz sine wave
Sample frequency is 500Hz
The analogy signal are generally
y(t) = Asin(2πx/λ - wt), w=2πf
y1(t)=Asin(2πx/λ - wt)
y1(t)=Asin(2πx/λ - 2π•25t)
y1(t)=Asin(2πx/λ - 50πt)
Similarly
y2(t)=Asin(2πx/λ - 150πt)
Using Nyquist theorem
Nyquist Theorem states that in order to adequately reproduce a signal it should be periodically sampled at a rate that is 2 times the highest frequency you wish to record.
From sampling
f(nyquist)=f(sample)/2
f(nyquist)=500/2
f(nyquist)=250Hz
From signal
The highest frequency is 150Hz
F(nyquist) = 2×F(highest)
f(nyquist)= 2×150
f(nyquist)= 300Hz
Sample per frequency Ns is given as
Ns=F(sample)/F(highest signal)
Ns=500/150
Ns=3.33sample/period
This is above nyquist rate of 2sample/period
So signal below 300Hz reproduced without aliasing.
The highest resulting frequency is 300Hz
<span>The question is asking us what is BEST to say about a runner who is running at a constant velocity? A constant velocity (=speed) means that they are not getting faster or slower - they are running exactly as fast all the time. This meanst that their speed does not change, so their change of speed is equal to 0. A change of speed is called acceleration so their C. Their acceleration is zero. - C is the correct answer. </span>
Answer:
Distance = 25000000 miles
Time = 50 hours
Explanation:
Venus is the closest planet to Earth. It is about 25 million miles away from Earth. Its precise distance depends on where both Venus and Earth are in their respective orbits
Given that
Speed V = 500000 mph
Distance d = 25 000,000 miles
Speed = distance/ time
Time = distance/speed
Time = 25000000/500000
Time = 50 hours
It will therefore take 50 hours to get to venus at that speed.
Answer:
Explanation:
Speed given = 125 m /min
125 /60 m /s
In 450 second it will travel
= 450 x 125 / 60
=937.5 m.
As the distance is covered in less than 450 seconds , The distance must be less than 937.5 m
In 400 seconds , it will travel
= 400 x 125 / 60
833.33 m
Since the distance is covered in more than 400 seconds , the distance must be more than ie 833.33 .
Hence the distance covered is more than .833 m but less than 937.5
In either case these distance are more than .8 km .
