1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
3 years ago
6

While the negatively charged rod is near the disk without touching it, a hand briefly touches the end of the post. Then the nega

tively charged rod is removed. What would happen to the vane?
Physics
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

Explanation:

Let us carefully analyze the situation, when the bar is facing the index post a load of equal magnitude, but opposite sign on its surface, these two charges are in balance; When the hand touches the pole, it creates a path to the ground where the charges that were induced on the pole can be balanced with the charge coming from the ground, leaving a zero charge on the pole.

 

   Now if the hand is removed, there can be no exchange of charges with the earth. When the bar is removed, the induced loads are redistributed in the post, but the excess loads that came from the earth that have the same value and are of a sign opposite to the induced ones remain, you want to sign that they are of the same sign as the charges of the bar.

   In summary, after the process, the post has a load of equal magnitude and sign (negative) that of the bar.

   If we assume that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

You might be interested in
Unbalanced forces cause a change in motion.<br><br> How do you know this?
ololo11 [35]

Answer:

This happens in two ways. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

Explanation:

5 0
2 years ago
I will mark you brainlist!
kirill115 [55]
Tornado- Trees knocked down, debris everywhere, ground and dirt scattered.
7 0
3 years ago
A spring with a spring constant value of 125 N/m is compressed 12.2 cm by pushing on it with a 215 g block. When the block is re
allsm [11]

Answer:

v = 2.94 m/s

Explanation:

When the spring is compressed, its potential energy is equal to (1/2)kx^2, where k is the spring constant and x is the distance compressed. At this point there is no kinetic energy due to there being no movement, meaning the net energy in the system is (1/2)kx^2.

Once the spring leaves the system, it will be moving at a constant velocity v, if friction is ignored. At this time, its kinetic energy will be (1/2)mv^2. It won't have any spring potential energy, making the net energy (1/2)mv^2.

Because of the conservation of energy, these two values can be set equal to each other, since energy will not be gained or lost while the spring is decompressing. That means

(1/2)kx^2 = (1/2)mv^2

kx^2 = mv^2

v^2 = (kx^2)/m

v = sqrt((kx^2)/m)

v = x * sqrt(k/m)

v = 0.122 * sqrt(125/0.215)        <--- units converted to m and kg

v = 2.94 m/s

3 0
2 years ago
In the Bohr model of the hydrogen atom, the speed of the electron is approximately 2.2 106 m/s.
Murrr4er [49]

The central force acting on the electron as it revolves in a circular orbit is 9.52 \times 10^{-8} \ N.

The given parameters;

  • <em>speed of electron, v = 2.2 x 10⁶ m/s</em>
  • <em>radius of the circle, r = 4.63 x 10⁻¹¹ m</em>

<em />

The central force acting on the electron as it revolves in a circular orbit is calculated as follows;

F = \frac{M_e v^2}{r} \\\\

where;

M_e is mass of electron = 9.11 x 10⁻³¹ kg

F = \frac{(9.11 \times 10^{-31}) \times(2.2\times 10^6)^2 }{4.63 \times 10^{-11}} \\\\F = 9.52 \times 10^{-8} \ N

Thus, the central force acting on the electron as it revolves in a circular orbit is 9.52 \times 10^{-8} \ N.

Learn more about centripetal force here:brainly.com/question/20905151

8 0
2 years ago
Natalie lifts a 15-kg rock from the ground onto a 1.5 meter high wall. what is the amount of potential energy she has given the
Zina [86]
The amount of gravitational potential energy acquired by the rock is equal to:
\Delta U = mg \Delta h
where 
m is the mass of the rock
g is the gravitational acceleration
\Delta h is the increase in height of the rock

Substituting the data of the problem, we find
\Delta U=(15 kg)(9.81 m/s^2)(1.5 m)=220.7 J
So, Natalie gave 220.7 J of energy to the rock.
4 0
3 years ago
Other questions:
  • When you push on an object such as a wrench, a steel pry bar, or even the outer edge of a door, you produce a torque equal to th
    10·1 answer
  • The force component along the displacement varies with the magnitude of the displacement, as shown in the graph. (a) 0 to 1.0 m,
    6·1 answer
  • Of waterfalls with a height of more than 50 m , Niagara Falls in Canada has the highest flow rate of any waterfall in the world.
    12·1 answer
  • Imagine a particular exoplanet covered in an ocean of liquid methane. At the surface of the ocean, the acceleration of gravity i
    8·1 answer
  • What features make a question scientific, and why are some questions beyond the boundaries of scientific investigation?. .Cite a
    13·1 answer
  • Which fossil fuel is used the most for energy production?
    14·1 answer
  • You are a surgeon operating on a broken bone. You find a large area, swollen with blood, that surrounds the break site. What is
    12·2 answers
  • How much thermal energy does it take to raise the temperature of 2.5 kg of
    5·1 answer
  • TRUE OR FALSE. if an object covers equal distance at equal intervals of time, then it is moving at constant speed and not accele
    5·1 answer
  • What is the symbol for a change in position?<br> Ad<br> p<br> d<br> Ap
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!