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Alina [70]
3 years ago
5

Where would a car traveling on a roller coaster have the most potential energy

Physics
1 answer:
sveta [45]3 years ago
6 0

At the top because it has the most potential to  go down. meaning it is a greater distance

c. At the top

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A net force of 100 N is moving a mass with an acceleration of 5 m/s2. What is the mass of the object?
olya-2409 [2.1K]
Fnet=ma so m = fnet/a   100/5=20 the mass is 20
7 0
3 years ago
You are walking around your neighborhood and you see a child on top of a roof of a building kick a soccer ball. The soccer ball
irinina [24]

Answer:

69.58 m tall

Explanation:

Pls see attached file

3 0
3 years ago
a.Calculate the average speed (in km/h) of Charlie, who runs to the store 4 kilometers away in 30 minutes. b.Calculate the dista
sveta [45]

as per the question charlie runs to the store which is  4 km away

hence the total distance covered [S] is 4 km

he takes 30 minutes to reach the store.

hence the total time taken [t] = 30 minutes=0.5 hour

We have to calculate the average speed.

the average speed[v]= =\frac{S}{t}

                                   =\frac{4 km}{0.5 hour}

                                    =8 km/hour

then we have to calculate the total distance traveled by charlie in 1 hour.

the distance covered S= V_{avg} *t

                                      =8 km/hour ×1 hour

                                      =8 km

Hence the average speed of charlie is 8 km/hour and he covers a distance of 8 km in 1 hour.

7 0
3 years ago
A spelunker is surveying a cave. She follows a passage 140 m straight west, then 290 m in a direction 45? east of south, and the
zimovet [89]

Answer:

Magnitude of fourth displacement is approximately 95 metres,

Direction of fourth displacement is straight west.

3 0
3 years ago
A scuba diver at 70 m below the surface of a lake, where the temperature is 4 degrees C, releases an air bubble with a volume of
posledela

Answer:

121.3 cm^3

Explanation:

P1 = Po + 70 m water pressure (at a depth)

P2 = Po (at the surface)

T1 = 4°C = 273 + 4 = 277 K

V1 = 14 cm^3

T2 = 23 °C = 273 + 23 = 300 K

Let the volume of bubble at the surface of the lake is V2.

Density of water, d = 1000 kg/m^3

Po = atmospheric pressure = 10^5 N/m^2

P1 = 10^5 + 70 x 1000 x 10 = 8 x 10^5 N/m^2

Use the ideal gas equation

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

By substituting the values, we get

\frac{8\times 10^5\times 14}{277}=\frac{10^{5} \timesV_{2}}{300}

V2 = 121.3 cm^3

Thus, the volume of bubble at the surface of lake is 121.3 cm^3.

6 0
3 years ago
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