Question

Solve the equation 3(2^2x +3) - 5(2^2x+2) - 156 = 0 leaving your answer in logarithmic form​

Answer 1

Answer:

Hello,

Step-by-step explanation:

$3*2^{2x+3}-5*2^{2x+2}-156=0\\\\6*2^{2x+2}-5*2^{2x+2}=156\\\\2^{2x+2}=156\\\\(2x+2)*ln(2)=ln(156)\ (naturel\ logarithm)\\\\2x+2=\dfrac{ln(156)}{ln(2)} \\\\x=\dfrac{\dfrac{ln(156)}{ln(2)} -2}{2} \\\\x=\dfrac{ln(156)}{ln(4)}-1 \\x\approx{2,64270...}$